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3 years ago

WHOEVER IS THE FIRST ANSWER I'LL MARK THE BRAINIEST ANSWER!!!

Mathematics

1 answer:

Sauron [17]3 years ago

4 0

Answer:

4π

Step-by-step explanation:

find the circumference first

2π r

2π 8=16π

then find the arc length

16π * 1/4

4π

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A one day trip to new york, mary spent $6.25 for breakfast and 8.95 for lunch. She can spend no more than an average of $8.50. H

zysi [14]

Mary spent $10.30 on dinner to stay in budget.

Step-by-step explanation:

Amount spent on breakfast = $6.25

Amount spent on lunch = $8.95

Amount spent on dinner = x

Average = $8.50

Average = $\frac{Sum\ of\ values}{No.\ of\ values}$

$8.50 = \frac{6.25+8.95+x}{3}\\8.50=\frac{15.20+x}{3}$

Multiplying both sides by 3

$8.50*3=\frac{15.20+x}{3}*3\\25.50=15.20+x\\25.50-15.20=x\\x=10.30$

Mary spent $10.30 on dinner to stay in budget.

Keywords: Average, addition

Learn more about addition at:

#LearnwithBrainly

7 0

4 years ago

Find the area. Please help

Nutka1998 [239]

The answer to your question is 77 because the formula for area for a triangle is A=1/2BH and the base is 11 feet and the height is 14 feet. So, (14•11)/2 is 77. Therefore, 77 squared feet is the answer.

6 0

3 years ago

Which expression can be used to solve 3/5 divide by 7/10

kramer

Answer:

$\frac{3}{5} *\frac{10}{7}$

= $\frac{30}{35} =\frac{6}{7}$

7 0

4 years ago

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$