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3 years ago

The ratio of girls to boys who participated in the geography bee was 5:4 there were 36 total students how many were boys

Mathematics

1 answer:

Simora [160]3 years ago

5 0

There will be 20 boys in the class.

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Point C is on the segment AB which has endpoints A(-1, 0) and B(3, 8). Point C is three times as far from point A as it is from

Viefleur [7K]

Answer:

C = (2, 6)

Step-by-step explanation:

The coordinates of point C can be found as the weighted average of the endpoint coordinates. The weights are the reverse of the relative segment lengths.

For AC : CB = 3 : 1, we have ...

C = (A +3B)/(1+3) = ((-1, 0) +3(3, 8))/4 = (-1+9, 0+24)/4

C = (2, 6)

8 0

3 years ago

Find the H.C.F of 48,60 and 96. please no links . please step by step explanation

krek1111 [17]

Answer:

Do you mean GCF?

Step-by-step explanation:

48, 60, and 96 all have a GCF of 12

12 x 4 = 48

12 x 5 = 60

12 x 8 = 96

6 0

3 years ago

Simplify the expression.<br> (-3+6)(-3+5)

Kipish [7]

Answer:

Step-by-step explanation:

first you do -3+6 which is 3.

then, u do -3+5 which is 2

multiply it and u get 6

5 0

3 years ago

Tia cut 4 meter 8 centimeter wire into 10 equal pieces. Marta cut 540 centimeter wire into 9 equal pieces . How much longer is o

saveliy_v [14]

Answer:

19.2 centimeters

Step-by-step explanation:

Tia cut a 4 meter and 8 centimeter wire, converting this measure to centimeters

$4m + 8 cm = 400cm + 8cm =408 cm$

and she cut it into 10 equal pieces, thus each piece measures:

$\frac{408cm}{10}=40.8cm$ .

Martha has a wire of 540 centimeter wich she cutted into 9 equal pieces, so each piece measures:

$\frac{540cm}{9} =60cm$

The difference between the two wires is:

$60cm - 40.8cm=19.2cm$

7 0

3 years ago

Find the range of p in equation p(x+1) (x-3)=x-4p-2 has no real roots.

Tanya [424]

Answer:

$\displaystyle p > \frac{1}{4}$ .

Step-by-step explanation:

Expand the left-hand side of this equation:

$p\, (x + 1)\, (x - 3) = p\, \left(x^2 - 2\, x - 3\right) = p\, x^2 - 2\, p\, x - 3\, p$ .

Collect the terms, so that this quadratic equation is in the form $a\, x^2 + b\, x+ c = 0$ :

$p\, x^2 - 2\, p\, x - 3\, p = x - 4\, p - 2$ .

$p\, x^2 - (2\, p + 1)\, x + (p + 2) = 0$ .

In this equation:

$a = p$ .
$b = -(2\, p + 1)$ .
$c = p + 2$ .

Calculate the quadratic discriminant of this quadratic equation:

$\begin{aligned}b^2 - 4\, a\, c &= (-(2\, p + 1))^2 - 4\, p\, (p + 2) \\ &= 4\, p^2 + 4\, p + 1 - 4\, p^2- 8\, p = -4\, p + 1\end{aligned}$ .

A quadratic equation has no real root if its quadratic discriminant is less then zero. As a result, this quadratic equation will have no real root when $-4\, p + 1 < 0$ . Solve for the range of $p$ :

$\displaystyle p > \frac{1}{4}$ .

4 0

4 years ago