Answer:
OK=9.9
Step-by-step explanation:
KJ and LJ both are on the circumference, are secants and coincides at the same outer point so they are equal.
JK=LJ so JK=13.2
Tangents are perpendicular to radius so the triangle in the circle is a right triangle.
Apply pythagorean theorem to find OK
To express the value of the arc secant of the square root of 2 you must first express its cross multiplication process that having variable x as its total then you will came up with sec(x) =sqrt(2) then remember that sec() is equals to 1/cos(x), then its is 1/cos(x) = sqrt(2) then use the special triangle principles withe side length of 1,1 and sqrt(2) and the value of that is pi/4 so x= pi/4 then arcsec(sqrt(2)) = pi/4.
Answer:
If im not wrong, just multiply wxlxh, for all sides, and you get 1260.
Step-by-step explanation:
Answer:
Please see the matches between the equations provided with the data set below.
Step-by-step explanation:
A. y = 10x + 65
It matches with the data set located at the bottom right, where x represents the number of hours studied, and y represents the grade on test.
B. y = 2x - 1
It matches with the data set located at the top right, where we have:
x y
1 1
1.5 2
2 3
2.5 4
3 5
C. y = x + 2
It matches with the data set located at the bottom left, where:
x y
2 4
5 7
10 12
D. y = x - 0.50
It matches with the data set located at the top left, where:
x y
1 0.50
1.50 1
2 1.50
2.50 2
3 2.50
10 12