hey jay sorry for the phone number but i did not respond yet but i will text you back when you leave the office
The Lagrangian is
with critical points where the partial derivatives vanish.
Substitute 
into the last equation and solve for 
:
Then we get two critical points,
We get an absolute maximum of 
at the second point, and an absolute minimum of 
at the first point.
Answer:
k = 3
Step-by-step explanation:
If the line passing through the points A (-1,3k) and B (k , 3) is parallel to the line whose equation is 2y+3x=9, then their slopes are equal
For coordinate AB;
slope m1 = 3 - 3k/k-(-1)
m1 = 3-3k/k+1
For the line 2y+3x = 9
2y = -3x + 9
y = -3/2 x + 9/2
Slope m2 = -3/2
Since m1 = m2
3-3k/k+1 = -3/2
Cross multiply
2(3-3k) = -3(k+1)
Expand
6 - 6k = -3k - 3
-6k+3k = -3 - 6
-3k = -9
k = -9/-3
k = 3
Hence the value of k is 3
Answer:
Legenth times width
Step-by-step explanation:
Answer:
(32 ÷4) +8
Step-by-step explanation:
More than means it comes after
quotient of 32 and 4
32÷ 4
8 more than
(32 ÷4) +8
