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Lelu [443]
2 years ago
6

True or false? ( help me please and thank you)

Mathematics
2 answers:
Dmitriy789 [7]2 years ago
4 0

Answer:

False

Step-by-step explanation:

Well it's True in a way, but they didn't simplify all the way. Correct simplification would be 1/3

denis-greek [22]2 years ago
4 0

Answer:

It is true

Step-by-step explanation:

As a proportion, they are equal, making it true.

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The measure of angle A
wariber [46]

Answer:

A. Measure of angle A + measure of angle B

Step-by-step explanation:

Because angle 4 is an exterior angle of given triangle which will be equal to the Measure of angle 2 + measure of angle 3

6 0
2 years ago
Use completing the square to solve the equation x2 - 10x = -8.
Kay [80]

Answer:

x^2 - 10x + 25 = 17

Step-by-step explanation:

Please use " ^ " to denote exponentation:

x^2 - 10x = -8

x^2 - 10x + 25 = 17

x^2 - 10x + 25 = -8

x^2 - 10x - 25 = -33

Begin with x^2 - 10x = -8.  Here's the process for completing the square:

1.  Take half of the coefficient of x and square the result:

    (1/2)(-10) = -5, and then (-5)^2 = + 25

2.  Add this 25 to the first two terms of x^2 - 10x = -8 and also to the      constant -8:    x^2 - 10x + 25 = -8 + 25, or     x^2 - 10x + 25 = 17

3.  Match this result to one of the given possible answers.  Turns out that the given possible answer matching our result is the first one:

x^2 - 10x + 25 = 17

     

7 0
2 years ago
What is the domain and range of the function graphed below?
Nataliya [291]

Answer:

I think the answer is C.

Step-by-step explanation:

I hope this helps :)

6 0
2 years ago
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
3 years ago
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