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2 years ago

2.48030477 rounded to the nearest hundred-thousandth is

1 answer:

3 0

2.48030, its rounded tenths 2.5 hundreths 2.48 thousands 2.480 ten-thousands 2.4803 then hundred-thousandth 2.48030

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Find the m<bac, if m<dec= 58 and m<edc =43 a. 43 b. 58 c. 79 d. 101

mamaluj [8]

We are looking to figure out the size of m<CAB
Since line AB is parallel to the line CD, m<CAB corresponds to m<ECD which means the size of the angles equals
m<ECD can be found by using the fact that angles in a triangle add up to 180°,
hence, 180°-58°-43°=79°

The size of m<CAB is 79°

5 0

3 years ago

Read 2 more answers

One quart of water-resistant paint covers 75 square feet. A swimming pool is in the shape of a rectangular prism with a length o

docker41 [41]

18.66 quarts of paint is needed to paint the swimming pool with two coats of paint

Solution:

Given that,

A swimming pool is in the shape of a rectangular prism

Length = 20 feet

Width = 10 feet

Height = 5 feet

Find the surface area of prism

$A=2(wl+hl+hw)$

Where, "l" is the length and "w" is the width and "h" is the height

$A = 2(10 \times 20 + 5 \times 20 + 5 \times 10)\\\\A = 2(200+100+50)\\\\A = 2 \times 350\\\\A = 700$

Thus surface area area of prism is 700 square feet

Given that,

One quart of water-resistant paint covers 75 square feet

Therefore,

1 quart paint = 75 square feet

x quart = 700 square feet

This forms a proportion

$1 \times 700 = 75 \times x\\\\x = \frac{700}{75}\\\\x = 9.33$

Thus 9.33 quarts of paint is needed to cover 700 square feet

How many quarts should you buy to paint the swimming pool with two coats of paint

For two coats of paint we need = 9.33 + 9.33 = 18.66 quarts of paint

4 0

2 years ago

Does anyone know how to solve |4x+3|-9<5

elixir [45]

Answer in fraction form: -17/4 < x < 11/4

Answer in decimal form: -4.25 < x < 2.75

=======================================================

Work Shown:

|4x+3| - 9 < 5

|4x+3| < 5+9 .... adding 9 to both sides

|4x+3| < 14

-14 < 4x+3 < 14 .... see note at the bottom

-14-3 < 4x < 14-3 .... subtracting 3 from all sides

-17 < 4x < 11

-17/4 < x < 11/4 .... divide all sides by 4

-4.25 < x < 2.75

This says that x is between -4.25 and 2.75, but x is not equal to either endpoint.

Note: I used the rule that |x| < k becomes -k < x < k where k is a positive real number.

6 0

2 years ago

What is .87890625 rounded to the nearest thousand

kotykmax [81]

Answer:

To the nearest thousand would be 0, on the other hand, to the nearest thousandth would be .879

5 0

2 years ago

Read 2 more answers

In problem solve the given differential equation by underdetermined coefficients y''-2y+y=xe^x

Alexus [3.1K]

Answer:

Solution is $y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}$

Step-by-step explanation:

Given Differential Equation,

$y"-2y'+y=xe^x$ ...............(1)

We need to solve the given differential equations using undetermined coefficients.

Let the solution of the given differential equation is made up of two parts. one complimentary solution and one is particular solution.

$\implies\:y(x)=y_c(x)+y_p(x)$

For Complimentary solution,

Auxiliary equation is as follows

m² - 2m + 1 = 0

( m - 1 )² = 0

m = 1 , 1

So,

$y_c(x)=C_1e^x+c_2xe^x$

Now for particular solution,

let $y_p(x)=Ax^3e^x$

$y'=Ax^3e^x+3Ax^2e^x$

$y"=Ax^3e^x+6Ax^2e^x+6Axe^x$

Now putting these values in (1), we get

$Ax^3e^x+6Ae^2e^x+6Axe^x-2(Ax^3e^x+3Ax^2e^x)+Ax^3e^x=xe^x$

$Ax^3e^x+6Ae^2e^x+6Axe^x-2Ax^3e^x-6Ax^2e^x+Ax^3e^x=xe^x$

$6Axe^x=xe^x$

$6A=1$

$A=\frac{1}{6}$

$\implies\:y_p(x)=\frac{x^3e^x}{6}$

Therefore, Solution is $y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}$

8 0

3 years ago