All categories

2 years ago

Please help me take this pleaseee

Mathematics

2 answers:

Oksi-84 [34.3K]2 years ago

7 0

Answer:

3x² + 2x + 18

Step-by-step explanation:

24x² + 16x + 144 .......simplify by 4

6x² + 4x + 36

3x² + 2x + 18

Travka [436]2 years ago

7 0

Answer:

Step-by-step explanation:

3*8=24

2*8=16

18*8=144

then you put the variables behind em :)

You might be interested in

What’s this <br> hdhshxbbsncjdkckskxbsh

7nadin3 [17]

Answer:

i dunno what that means but i think maybe your keyboard broke so the type of letters is random??

5 0

3 years ago

A triangle with two 8

tekilochka [14]

Answer:

One unique triangle

Step-by-step explanation:

3 0

2 years ago

the five performers who will present their comedy acts this weekend at a comedy club how many different ways are there to schedu

wlad13 [49]

First day 1 in morning after noon and night next day one in morning and night

8 0

3 years ago

Read 2 more answers

Racionalize o denominador da equação abaixo:<br> 5 + 3 ²√5 / ²√5

GrogVix [38]

I hope this helps

$\cfrac{5+3 \sqrt{5} }{ \sqrt{5} } =\cfrac{(5+3 \sqrt{5}) \sqrt{5} }{ \sqrt{5}* \sqrt{5} }= \cfrac{5 \sqrt{5}+15 }{5} = \cfrac{5 (\sqrt{5}+3) }{5} = \sqrt{5}+3$

4 0

3 years ago

g 78% of all Millennials drink Starbucks coffee at least once a week. Suppose a random sample of 50 Millennials will be selected

Tatiana [17]

Answer:

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

$np=50*0.78=39 \geq 10$

$n(1-p)=50*(1-0.78)=11 \geq 10$

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}})$

With the following parameters:

$\mu_ p = 0.78$

$\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

$np=50*0.78=39 \geq 10$

$n(1-p)=50*(1-0.78)=11 \geq 10$

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}})$

With the following parameters:

$\mu_ p = 0.78$

$\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586$

6 0

3 years ago