The critical points of a rational inequality are -1, 3, and 4. Which set of points can be tested to find a complete solution
2 answers:
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Answer:
<h2>A) a - 1 and B) a + 2</h2>Step-by-step explanation:
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now on 2)
if the denominator has a higher degree than the numerator, the horizontal asymptote is y = 0, or the x-axis,
in this case, the numerator has a degree of 0, the denominator has 4, thus y = 0
vertical asymptotes occur when the denominator is 0, that is, when the fraction becomes undefined, and for this one, that occurs at or the y-axis
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now on 3)
now, let's see some transformations templates
now, let's take a peek at g(x)
Answer:
A. The graph is not proportional, although it has a consistent slope, it does now go through the point of origin or (0,0). The equation of a proportional line is y=kx, so the y-intercept must be at (0,0).
B. Slope is found by , from 1 point to the next, the y-value (rise) increases by 2 and the x-value (run) increases by 1,
giving us a slope of 4.
C. The y-intercept is the lines point of intersection with the y-axis. In the graph, this point is (0,10).
D. y = mx + b is the slope-intercept form where m is the slope and b is the y-intercept, the slope (m) is 4 and the y-intercept (b) is 10. y = 4x + 10
E. The equation is not proportional because the b value is 10 rather than 0.