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Allisa [31]
3 years ago
9

Eveloped By An Engine With A Displacement Of 220 Cu In. If A 360 Cu In. Engine Of The Same Kind Develops 210 Hp? This problem ha

s been solved! See the answer hoserpower developed by an engine varies directly as its displacement. How many horsepower will be developed by an engine with a displacement of 220 cu in. If a 390cu in. Engine of the same kind develops 230hp?
Mathematics
1 answer:
exis [7]3 years ago
5 0

Answer:

  about 130 hp

Step-by-step explanation:

The displacement is smaller by a factor of 220/390, so we expect the horsepower to be smaller than 230 hp by the same factor:

  (220/390)(230 hp) ≈ 129.74 hp ≈ 130 hp

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Place Math Quiz
Aleksandr [31]

Answer:

c) $136,800

Step-by-step explanation:

Since the thing is 3 years and in 3 year there are 36 months. And since $3,800/mo so 36 x 3,800 = 136,800

So the answer is $136,800

6 0
3 years ago
Use substitution to solve the problem below algebraically.<br><br> x = 41<br> x + 2y = 71
grandymaker [24]

Answer:

41 + 2y = 71

2y = 30

y = 15

Step-by-step explanation:

i believe that is right, if not sorry

7 0
3 years ago
Read 2 more answers
HELP! Identify the equation of the circle that has its center at (-3, -4) and passes through the origin.
Lunna [17]

Answer:

Option B. (x+3) ^2+(y+4)^2=25

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

(x-h)^{2}+(y-k)^{2}=r^{2}

where

(h,k) is the center and r is the radius

step 1

Find the radius of the circle

Remember that the distance of the center and any point on the circle is equal to the radius of the circle

so

Find the distance between the points (-3,-4) and (0,0)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

substitute

r=\sqrt{(0+4)^{2}+(0+3)^{2}}

r=\sqrt{(4)^{2}+(3)^{2}}

r=\sqrt{25}

r=5\ units

step 2

Find the equation of the circle

(x-h)^{2}+(y-k)^{2}=r^{2}

the center is the point (-3,-4) and the radius is r=5 units

substitute

(x+3)^{2}+(y+4)^{2}=5^{2}

(x+3)^{2}+(y+4)^{2}=25

6 0
3 years ago
Question 12(Multiple Choice Worth 1 points)
daser333 [38]

The equation of a line is y=-1/4x-7, (option 1)

<h3>What is the equation of a line? </h3>

A straight line's general equation is y = mx + c, where m denotes the gradient and y = c denotes the point at which the line crosses the y-axis.

<h3>How do you find the equation of a line?</h3>

Write the equation in the form y = mx + b to find the slope m and the y-intercept. This will allow you to graph the equation using the slope and y-intercept.

Given:-

Equation of the line is y=4x+8 

The point through which the line passes (-8,4).

here the slope of the line is m1=4

To find the perpendicular line we know the formula

m1*m2=-1

By putting the value of m1 we get m2= -1/4

By using the one-point formula of the line we have

=>(y-y1)=m2*(x-x1)

By putting the values of y1 and x1 we get

(y1,x1)=(-8,4)

=>(y+8)=-0.25*(x-4)

y+0.25x+7=0

Hence the desired equation of the line is y=-1/4x-7

To find more about the straight line equations visit :

brainly.com/question/25969846

#SPJ1

7 0
1 year ago
What is 4.3 x 10 is it 43 yes or no
natka813 [3]
The answers is correct yes
3 0
4 years ago
Read 2 more answers
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