Pecting Java<span> 2's </span>stack inspection<span> policy to be enforced can-. not execute on .... Figure 2. PSLang security policy that </span>allows<span> at most 10 open windows. .... </span>Method<span> call/return: A → B. At start of B, look up</span>protection<span> domain PB for B's. code and push PB on the thread-local domain-. </span>Stack<span>. At return from B (either normally or by.</span>
Answer:
d. d1− = 10, d1+ = 0
Explanation:
Given
3X1 + 4X2 +d1− − d1+ = 36
X1 = 6
X2 = 2
Required
Possible values of d1- and d1+
We have:
3X1 + 4X2 +d1− − d1+ = 36
Substitute values for X1 and X2
3 *6 + 4 * 2 + d1- - d1+ = 36
18 + 8 + d1- - d1+ = 36
Collect like terms
d1- - d1+ = 36 - 18 - 8
d1- - d1+ = 10
For the above equation to be true, the following inequality must be true
d1- > d1+
Hence,
(d) is correct
Because:
10 > 0
Answer:
Type right under my comment
Explanation:
Look in comments
Answer:
20
Explanation:
assuming the print statement is not indented, the program effectively calculates 2+5+6+7.
The range(...) is <em>excluding </em>the end value (8 in this case).
