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Naddik [55]
3 years ago
12

Please help! I’ll mark you as brainliest if correct!

Mathematics
1 answer:
pickupchik [31]3 years ago
7 0
9, because it says “all but 9” get mushed, which means 9 are in good condition.


:) hope this helps! Can I please have brainliest, I’m trying to level up.
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I hope this is worth a Brainliest!

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Read 2 more answers
Chocolate chip cookies have a distribution that is approximately normal with a mean of 23.6 chocolate chips per cookie and a sta
nikklg [1K]

Answer:

Those values can be helpul to find an ideal range for the number of chocolate chips per cookie.

P(5) = 19.82 chips per cookie.

P(95) = 27.38 chips per cookie.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 23.6, \sigma = 2.3

How might those values be helpful to the producer of the chocolate chip​ cookies?

Those values can be helpul to find an ideal range for the number of chocolate chips per cookie.

P(5)

5th percentile, which is the value of X when Z has a pvalue of 0.05. So it is X when Z = -1.645.

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 23.6}{2.3}

X - 23.6 = -1.645*2.3

X = 19.82

P(5) = 19.82 chips per cookie.

P(95)

95th percentile, which is the value of X when Z has a pvalue of 0.95. So it is X when Z = 1.645.

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 23.6}{2.3}

X - 23.6 = 1.645*2.3

X = 27.38

P(95) = 27.38 chips per cookie.

8 0
3 years ago
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