Answer:
Well we add together 20+15 which is 35 which is 5 over the 30 in the class so that means out of the 30 students 5 of them like both games
Hope This Helps
Answer:

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795
Step-by-step explanation:
Given
See attachment for class
Solving (a): Fill the midpoint of each class.
Midpoint (M) is calculated as:

Where
Lower class interval
Upper class interval
So, we have:
Class 63-65:

Class 66 - 68:

When the computation is completed, the frequency distribution will be:

Solving (b): Mean and standard deviation using 1-VarStats
Using 1-VarStats, the solution is:


<em>See attachment for result of 1-VarStats</em>
September
30-10=20 days
October 31
November 10
Time=20+31+10=61 days
A=42,000×(1+0.035÷365)^(61)
A=42,246.38
Interest earned
I=42,246.38−42,000
I=246.38
Answer:
B
Step-by-step explanation:
We can't see the answer choices?