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kumpel [21]
2 years ago
5

Find the product of largest 4 digit number andsmallest 3 digit number.​

Mathematics
2 answers:
Afina-wow [57]2 years ago
3 0
Largest 4 digit number =9999
Smallest 3 digit number= 100
So the product of 9999 x 100 = 999,900
Andrews [41]2 years ago
3 0

Answer:

Largest 4-digit number is 9999 and smallest 3-digit number is 100 and product is 10000.

Step-by-step explanation:

hope it's helpful to you

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Answer:

The correct answer is D 46.3644



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3 years ago
A 6-sided die is rolled. what is the probability of rolling a number less than 4?
ohaa [14]

1/2

Step-by-step explanation:

All outcomes of a single die= 6

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probability=3/6

=1/2

7 0
1 year ago
It takes you 0.8 of a minute to read each page of your health book.It takes you 5.5 minutes to take the test at the end.How long
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So you divide 0.8 by 6.25 and your answer is 7.8125 and then you add 5.5 minutes of your other number and you get the answer of  13.3125
6 0
3 years ago
In the game of​ roulette, a player can place a ​$9 bet on the number 11, and have a 1/38 probability of winning. If the metal ba
damaskus [11]

Answer:

1. What is the expected value of the game to the​ player?

Expected value= -$0.47368

2. If you played the game 1000​ times, how much would you expect to​ lose?

Expected value= -$473.68

Step-by-step explanation:

1. What is the expected value of the game to the​ player?

Expected value can tell how much you will gain/lose every time you do the game. To find the expected value you need to multiply every value with its chance to occur. There are two types of events here, winning and losing. You have 1/38 chance of winning $315 and 37/38 chance of losing $9.  

The expected value will be:

expected value= 1/38 * $315 + 37/38*(-$9) = $8.2894 - $8.7631

expected value= -$0.47368

You are expected to lose $0.47368 every time you play

2. If you played the game 1000​ times, how much would you expect to​ lose?

Expected value calculated for each roll. If you want to know how much you gain/lose by multiple rolls, you just need to multiply the expected value with the number of rolls. The game has negative expected value so you are expected to lose money instead of gaining money. The money you expected to lose will be:

number of roll * expected value

1000 timer * -$0.47368/time= -$473.68

You are expected to lose $473.68 if you play the game 1000 times.

6 0
3 years ago
1/2 (12+8) • 52 - 17=_
qwelly [4]
The answer to your question is 503
5 0
3 years ago
Read 2 more answers
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