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insens350 [35]
3 years ago
5

A bag contains 7 red marbles, 5 blue marbles, and 2 green marbles. What is the probability of choosing a blue marble when one ma

rble is drawn?
Mathematics
2 answers:
blsea [12.9K]3 years ago
6 0

Answer:

a red

Step-by-step explanation:

A bag contains 7 red marbles, 5 blue marbles, and 2 green marbles. What is the probability of choosing a blue marble when one marble is drawn?

Vitek1552 [10]3 years ago
3 0

Answer:

5/14

Step-by-step explanation:

7+5+2=14 and there are 5 blue marbles to the answer is just the ratio of blue marbles to total marbles.

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2 questions, all help is welcomed, I am very desperate yall thanks~!
skad [1K]
The answer for question number 1 is : 2x + 4
and for question number 2 : 10
7 0
3 years ago
Please help! posted picture of question
o-na [289]
C. 5x - 2y = 16 is your answer

plug in each point into the equation.

(2, -3)

x = 2, y = -3

5(2) - 2(-3) = 16
10 + 6 = 16
16 = 16 (True)

(4,2)

x = 4, y = 2

5(4) - 2(2) = 16
20 - 4 = 16
16 = 16 (True)


hope this helps
4 0
3 years ago
Read 2 more answers
Health insurers are beginning to offer telemedicine services online that replace the common office visit. A company provides a v
Veronika [31]

Answer:

\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

Step-by-step explanation:

Let us find out the mean savings for a televisit to the doctor from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

\bar{x} = \$71  

Let us find out the standard deviation of savings for a televisit to the doctor from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

 s = \$ 22.35

The confidence interval is given by

\text {confidence interval} = \bar{x} \pm MoE\\\\

Where the margin of error is given by

$ MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) $ \\\\

Where n is the sample of 20 online doctor visits, s is the sample standard deviation and t_{\alpha/2} is the t-score corresponding to a 95% confidence level.

The t-score is given by is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 20 - 1 = 19

From the t-table at α = 0.025 and DoF = 19

t-score = 2.093

So, the margin of error is

MoE = t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\MoE = 2.093\cdot \frac{22.35}{\sqrt{20} } \\\\MoE = 2.093\cdot 4.997\\\\MoE = 10.46\\\\

So the required 95% confidence interval is

\text {CI} = \bar{x} \pm MoE\\\\\text {CI} = 71 \pm 10.46\\\\\text {CI} = 71 - 10.46, \: 71 + 10.46\\\\\text {CI} = (60.54, \: 81.46)\\\\

Therefore, we are 95% confident that actual mean savings for a televisit to the doctor is within the interval of ($60.54 to $81.46)

7 0
3 years ago
A playhouse is in the shape of a regular octagonal pyramid with a side length of 3 feet and a slant height of 12 feet. The wood
g100num [7]
I believe it is 144 dollars
3 0
3 years ago
Read 2 more answers
2-8x+12=5(x-7) what is the solution
navik [9.2K]
2-8x+12=5(x-7)
-8x+14=5x-35
-8x-5x=-35-14
-13x=-49
x=-49/-13=49/13

Solution :   x=49/13

7 0
3 years ago
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