Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
Since you don't provide the coordinates of the point W, I will help you in a general form anyway. In the Figure below is represented the segment that matches this problem. We have two endpoints U and V. So, by using the midpoint formula we may solve this problem:
Therefore:
So we know 
but we also must know 
Finally, knowing the points U and W we can find the endpoint V.
43.71, 43.6, 41.92 greatest to least
3(2v+5)=33
Simplify both sides of the equation
3(2v+5)=33
Distribute
(3)(2v)+(3)(5)=33
6v+15=33
Subtract 15 from both sides
6v+15-15=33-15
6v=18
Divide both sides by 6
6v/6=18/6
V= 3
I hope that's help !
