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Soloha48 [4]
3 years ago
15

Vertical angles must:Check all that apply. A.be complementary. B.be acute. C.have the same vertex. D.be congruent.

Mathematics
1 answer:
KIM [24]3 years ago
3 0
<span>Vertical angles must be C and D

A.be complementary. They are not always complementary, to be complementary means having a sum of 90 deg
B.be acute. - Vertical angles can be NOT acute depending on how they are positioned and intersected with the lines.

Answer
C.have the same vertex.
D.be congruent.</span>
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Answer:

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8 0
3 years ago
Solve 29 – 3:= 5x + 5 for x.​
mojhsa [17]

Answer:

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Answer: x = 6

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5 0
2 years ago
Find the equation of a sphere if one of its diameters has endpoints: (-9, -12, -6) and (11, 8, 14).
baherus [9]

Answer:

Hence, the equation of a sphere with one of its diameters with endpoints (-9, -12, -6) and (11, 8, 14) is (x-1)^{2}+(y+2)^{2}+(z-4)^{2} = 30.

Step-by-step explanation:

There are two kew parameters for a sphere: Center (h, k, s) and Radius (r). The radius is the midpoint of the line segment between endpoints. That is:

C(x,y,z) = \left(\frac{-9+11}{2},\frac{-12+8}{2},\frac{-6+14}{2}   \right)

C(x,y,z) = (1,-2,4)

The radius can be found by halving the length of diameter, which can be determined by knowning location of endpoints and using Pythagorean Theorem:

r = \frac{1}{2}\cdot \sqrt{(-9-11)^{2}+(-12-8)^{2}+(-6-14)^{2}}

r = 10\sqrt{3}

The general formula of a sphere centered at (h, k, s) and with a radius r is:

(x-h)^{2}+(y-k)^{2}+(z-s)^{2} = r^{2}

Hence, the equation of a sphere with one of its diameters with endpoints (-9, -12, -6) and (11, 8, 14) is (x-1)^{2}+(y+2)^{2}+(z-4)^{2} = 30.

8 0
3 years ago
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densk [106]

Answer:

the answer is C

Step-by-step explanation:

4 0
3 years ago
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