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3 years ago

Vertical angles must:Check all that apply. A.be complementary. B.be acute. C.have the same vertex. D.be congruent.

1 answer:

3 0

Vertical angles must be C and D

A.be complementary. They are not always complementary, to be complementary means having a sum of 90 deg
B.be acute. - Vertical angles can be NOT acute depending on how they are positioned and intersected with the lines.

Answer
C.have the same vertex.
D.be congruent.

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Solve this problem 7|8-3h|=21h-49

tatiyna

Answer:

h=5/2

Step-by-step explanation:

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3 years ago

If 3 bars of chocolate cost $15.00 ghana cedis how much will 7 bars cost ratio

Rudiy27

Answer:

7 chocolate bars will cost $35

Step-by-step explanation:

if 3 cost $15 then 1 bar would cost 5 dollars and 5x7=35

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3 years ago

A worker can assemble 3 shelf units each hour. During the fifth hour of the shift, there were 115 shelf units in the warehouse.

nasty-shy [4]

A worker can assemble 3 shelf units each hr. During the 5th hr...so the shift has been going on for 5 hrs...at 3 units per hr = (3 * 5) = 15 units assembled during the shift....and if there was 115 units in the warehouse, then that means before the shift, there were (115 - 15) = 100 units assembled <=

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3 years ago

During a 5-day work week, pete was sick for 2 days .what fraction of the work week was he sick?

timofeeve [1]

I think the answer is 2/5

6 0

2 years ago

The figure below is a square. Find the length of side x in simplest radical form with a rational denominator.

Mashcka [7]

Answer:

$\frac{\sqrt{10}}{2}$

Step-by-step explanation:

The diagonal forms two 45-45-90 triangles, with the diagonal being the hypotenuse of both. The Pythagorean Theorem states that $a^2+b^2=c^2$ , where $c$ is the hypotenuse of the triangle, and $a$ and $b$ are the two legs of the triangle.

From the Isosceles Base Theorem, the two legs of a 45-45-90 triangle are always equal. Since we're given a diagonal of $\sqrt{5}$ , we have:

$x^2+x^2=\sqrt{5}^2,\\2x^2=5,\\x^2=\frac{5}{2},\\x=\sqrt{\frac{5}{2}}=\frac{\sqrt{5}}{\sqrt{2}}=\frac{\sqrt{5}}{\sqrt{2}}\cdot \frac{\sqrt{2}}{\sqrt{2}}=\boxed{\frac{\sqrt{10}}{2}}$

7 0

3 years ago