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Mashutka [201]
3 years ago
8

Brenda’s bank offers car financing for 3, 4 or 5 years. If brenda chooses 5-year financing, how many monthly payments will she h

ave?
Mathematics
1 answer:
klemol [59]3 years ago
7 0
The number of monthly payments Brenda will have will be given by:
Number of payments=[Number of years]×[number of months]
Number of years=5
Number of months=12
hence
# Payments=5*12=60 monthly payments
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I need this ASAP: <br> Find the volume
uysha [10]
It is A.

V=length x width x height
3x9=54
54x9=486
4 0
3 years ago
Please help thank you
Doss [256]

Answer:

x ≥ -4

Step-by-step explanation:

you subtract 10 on both sides to get x by itself. 6-10 = -4. since you already have x by itself you don’t have to do anymore

5 0
3 years ago
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Is 2y+4=2(y+2) one solution or no solution?
Olegator [25]
2y+4=2(y+2)
2y+4=2y+4
4=4
so the answer is all real numbers or infinite solutions
8 0
3 years ago
How many revolutions will a car wheel of diameter 22 in. make as the car travels a distance of one mile
Marianna [84]

It would be take upto 999 revolutions.

<em>Let try to solve it,</em>

Let n represent number of revolutions.

We are asked to find the number of revolutions it will take for a car wheel of diameter 30 in. to travel a distance of one mile.

1 mile = 63360 inches.

We will use circumference of circle formula to solve our given problem.

Circumference = pi*d , where, D represents diameter of circle.

Now, we will set the product of n and circumference of circle equal to 63360 inches as:

pi*22*n= 63360

n= 63360*7/ 22*22

n= 443520/444

n= 998.91

Therefore It would be take upto 999 revolutions.

Learn more about Circumference of circle on:

brainly.com/question/18571680

#SPJ4

8 0
2 years ago
Suppose that poaching reduces the population of an endangered animal by
Sedbober [7]

Answer:

38.26 years.

Step-by-step explanation:  

We have been given that the population of an endangered animal by  reduces 8​% per year. the current population of the animal is  1700. When the population of this animal falls below  70​, its extinction is inevitable.  

Let us write the model for population of this animal (y) after x years.

Since we know that an exponential decay function is in form: y=a*(1-r)^x, where,

a= Initial value.

r = Rate in decimal form.

Let us convert our given rate in decimal form.

8\%=\frac{8}{100}=0.08

Upon substituting a= 1700 and r = 0.08 in exponential function, we will get the model of animal population as:

y=1700*(1-0.08)^x

y=1700*(0.92)^x

Let us find, when the animal population will face extinction by substituting y=70 in our function.

70=1700*(0.92)^x  

\frac{70}{1700}=\frac{1700*(0.92)^x}{1700}

0.0411764705882353=0.92^x  

Let us take natural log of both sides of our equation.

ln(0.0411764705882353)=ln(0.92^x)

ln(0.0411764705882353)=x*ln(0.92)

-3.1898882879949483163=x*-0.0833816089390511

x=\frac{-3.1898882879949483163}{-0.0833816089390511}

x=38.2564971890460849445284\approx 38.26

Therefore, the population of the animal will face extinction after 38.26 years.

5 0
4 years ago
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