Answer:
II. One and only one solution
Step-by-step explanation:
Determine all possibilities for the solution set of a system of 2 equations in 2 unknowns. I. No solutions whatsoever. II. One and only one solution. III. Many solutions.
Let assume the equation is given as;
x + 3y = 11 .... 1
x - y = -1 ....2
Using elimination method
Subtract equation 1 from 2
(x-x) + 3y-y = 11-(-1)
0+2y = 11+1
2y = 12
y = 12/2
y = 6
Substitute y = 6 into equation 2:
x-y = -1
x - 6 = -1
x = -1 + 6
x = 5
Hence the solution (x, y) is (5, 6)
<em>Hence we can say the equation has One and only one solution since we have just a value for x and y</em>
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Answer:
~8.66cm
Step-by-step explanation:
The length of a diagonal of a rectangular of sides a and b is

in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:

Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths
is

So the solution here is

Answer:
log 5
Step-by-step explanation:
We can rewrite this by using a property of logs
log a - log b = log (a/b)
log(10) - log(2)
log(10/2)
log 5
110+90+145=345
345 divided by 3=115
so the score of her third game was 145 points.
hope i helped! :)
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