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nirvana33 [79]
2 years ago
5

When h has the value 12 calculate 5h - 2

Mathematics
1 answer:
yarga [219]2 years ago
7 0

Answer:

5h - 2

<em>(</em><em>5</em><em>×</em><em>1</em><em>2</em><em>)</em><em>-</em><em>2</em>

<em>6</em><em>0</em><em>-</em><em>2</em>

<em>=</em><em><u>5</u></em><em><u>8</u></em>

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Determine all possibilities for the solution set of a system of 2 equations in 2 unknowns. I. No solutions whatsoever. II. One a
Minchanka [31]

Answer:

II. One and only one solution

Step-by-step explanation:

Determine all possibilities for the solution set of a system of 2 equations in 2 unknowns. I. No solutions whatsoever. II. One and only one solution. III. Many solutions.

Let assume the equation is given as;

x + 3y = 11 .... 1

x - y = -1 ....2

Using elimination method

Subtract equation 1 from 2

(x-x) + 3y-y = 11-(-1)

0+2y = 11+1

2y = 12

y = 12/2

y = 6

Substitute y = 6 into equation 2:

x-y = -1

x - 6 = -1

x = -1 + 6

x = 5

Hence the solution (x, y) is (5, 6)

<em>Hence we can say the equation has One and only one solution since we have just a value for x and y</em>

<em />

4 0
3 years ago
The diagram shows a 5 cm x 5 cm x 5 cm cube.
mylen [45]

Answer:

~8.66cm

Step-by-step explanation:

The length of a diagonal of a rectangular of sides a and b is

\sqrt{a^2+b^2}

in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:

\sqrt{\sqrt{a^2+b^2}^2 + c^2} = \sqrt{a^2+b^2+c^2}

Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths a_1, a_2, a_3, \ldots, a_n is

\sqrt{a_1^2 + a_2^2 + a_3^2 + \ldots + a_n^2}

So the solution here is

\sqrt{(5cm)^2 + (5cm)^2 + (5cm)^2} = \sqrt{75cm^2} = 5\sqrt{3cm^2} \approx 5\cdot 1.732cm = 8.66cm

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2 years ago
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serg [7]

Answer:

log 5

Step-by-step explanation:

We can rewrite this by using a property of logs

log a - log b = log (a/b)

log(10) - log(2)

log(10/2)

log 5

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3 years ago
Saturday, nola bowled 3 games in her bowling league. she had a mean score of 115. the score of her first game was 110. the score
Elina [12.6K]
110+90+145=345
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