The answer is D. ∠FVI and ∠GVE. An obtuse angle must be wider than 90° (like the corners of a square or rectangle) and less than 180° (literally a straight line).
What is the domain of the given function? LaTeX: {(3, –2), (6, 1), (–1, 4), (5, 9), (–4, 0)} ( 3 , – 2 ) , ( 6 , 1 ) , ( – 1 , 4
Musya8 [376]
Given:
![\text{Function}=\{(3, -2), (6, 1), (-1, 4), (5, 9), (-4, 0)\}](https://tex.z-dn.net/?f=%5Ctext%7BFunction%7D%3D%5C%7B%283%2C%20-2%29%2C%20%286%2C%201%29%2C%20%28-1%2C%204%29%2C%20%285%2C%209%29%2C%20%28-4%2C%200%29%5C%7D)
To find:
The domain of the given function.
Solution:
Domain is the set of input values or x-values.
In the given function, the x-coordinates of ordered pairs are 3, 6, -1, 5 and -4. So, domain is the set of these values in ascending order.
The set builder form of domain is
![\text{Domain}=\{x|x=-4,-1,3,5,6\}](https://tex.z-dn.net/?f=%5Ctext%7BDomain%7D%3D%5C%7Bx%7Cx%3D-4%2C-1%2C3%2C5%2C6%5C%7D)
Therefore, the correct option is C.
Ok so if the equation is this
8x/8( 5 exponent) = 8 (7 exponent) the answer should be 8( 11 exponent)
My work is attached below.
Sorry for my awful handwriting!
Spinner diagram isn't attached. A related spinner diagram has been attached below to provide an hypothetical solution to the problem
Answer:
4 / 15
Step-by-step explanation:
For the numbered spinner :
P(landing on 2) = required outcome / Total possible outcomes
Total possible outcomes = (1, 2, 3) = 3
Required outcome = (1) = 1
P(landing on 2) = 1 /3
Lettered spinner :
P(does not land on b)
Total possible outcomes = (A, B, C, D, E)
Required outcome = (a, c, d, e)
P(does not land on b) = 4 / 5
Hence,
P(lands on 2, does not land on b) in this scenario is :
1/3 * 4/5 = 4 / 15