Answer: The 90% confidence interval for the population mean μ is between 82.85 and 85.15,
Step-by-step explanation:
When population standard deviation is not given ,The confidence interval population proportion is given by (
):-
, where n= Sample size.
s= Sample standard deviation
= sample mean
t* = Critical t-value (Two-tailed)
As per given , we have
n= 64
Degree of freedom : df = n-1=63
s= 5.5
Significance level : 
Two-tailed T-value for df = 63 and
would be
(By t-distribution table)
i.e. t*= 1.669
The 90% confidence interval for the population mean μ would be

∴ The 90% confidence interval for the population mean μ is between 82.85 and 85.15,
Answer: (2, -3)
Step-by-step explanation:
To find the the answer, you will need to use the midpoint formula, which is as following:
(x₁+x₂/2, y₁+y₂/2)
Since we have two coordinates, let's substitute them into the equation.
(7 + (-3 )/ 2, (-4) + (-2)/2)
We should first add 7 and -3 together, as well as -4 and -2.
(4/2, -6/2)
We then divide 4 and -6 by 2. This would give us our midpoint coordinate.
(2, -3)
15. -(-7y + 12) = 7y - 12
16. 1/a = 16/18
cross multiply
16a = 18
a = 18/16 = 9/8
17. 8x - 12 = 4x + 24
8x - 4x = 24 + 12
4x = 36
x = 36/4
x = 9
18. -6b > 42 4b > -4
b < 42/-6 b > -4/4
b < - 7 b > -1
so b < -7 and b > -1
19. 6 more then the product of 8 and n
6 + 8n
20. 45 = 3b + 69
45 - 69 = 3b
-24 = 3b
-24/3 = b
-8 = b