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Assoli18 [71]
3 years ago
10

***SOMEONE PLZ HELP ME***

Mathematics
1 answer:
Bingel [31]3 years ago
5 0
If the perimeter is 16, the side length is 4 units.

To find the area of the shaded sections, you will use the fractional part that each section represents and multiply that fraction by the total area of the square.

Area of DEA is 1/4 of 16 square Units (4 x 4).

1/4 x 16 = 4 square units

Area of EFB is 1/8 of 16 square units.

1/8 x 16 = 2 square units

4 square units +2 square units equals 6 square units.

The area of the shaded region is 6 square units.

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Can someone plz help me with this
Yakvenalex [24]
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4 0
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What is the area of this polygon?
ra1l [238]
Step 1) Draw a line from point F to point S. A rectangle forms (rectangle FSCW)

Step 2) Find the area of this rectangle. The area is 18 square units because it is 2 units high and 9 units across (9*2 = 18). You can count out the spaces or you can note how we go from x = -4 to x = 5 so subtracting the values gives -4-5 = -9 which has an absolute value of 9. 

Step 3) Find the area of triangle FSN. The base is 9 units and the height is 6 units (count out the spaces or subtract y values). So the area is A = b*h/2 = 9*6/2 = 54/2 = 27

Step 4) Add up the area of the rectangle to the area of the triangle: 18+27 = 45

Final Answer: 45 square units

note: another way to find the answer is to find the area of rectangle WABC where point A is at (-4,4) and point B is at (5,4). Then subtract off the triangular areas of AFN and BNS
6 0
3 years ago
Read 2 more answers
Find the area of quadrilateral ABCD
andreev551 [17]

Answer:

<em>A ≈ 28.5</em>

Step-by-step explanation:

a, b, c

P = a + b + c

Semiperimeter s = \frac{a+b+c}{2}

A = \sqrt{s(s-a)(s-b)(s-c)}

~~~~~~~~~~~~~~~

P_{ABC} = 4.3 + 2.89 + 6.81 = 14

s = 14 ÷ 2 = 7

A_{ABC} = \sqrt{7(7-4.3)(7-2.89)(7-6.81)} = √14.75901 ≈ 3.84

P_{BCD} = 8.59 + 7.58 + 6.81 = 22.98

s = 22.98 ÷ 2 = 11.49

A_{BCD} = \sqrt{11.49(11.49-8.59)(11.49-7.58)(11.49-6.81)} = √609.7343148 ≈ 24.6928

A_{ABCD} = 3.84 + 24.6928 ≈ <em>28.5</em>

3 0
3 years ago
WHAT IS EQUIVALENT TO THE INEQUALITY y/2 -6 &lt;8 ? PLEASE HURRY ITS DUE 10:50
Oksanka [162]
Y/2 - 6 < 8
y/2 < 14
y < 7
6 0
3 years ago
Read 2 more answers
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