2 years ago

Logarithmic differentiation: y=theta+8/theta *costheta

1 answer:

8 0

Y=Ф + 8/(ФcosФ) ==> note that

dy/dФ = 1 - 8/[(ФcosФ)]² x (-8sinФ) ==> dy/dФ = 1+[(64sinФ)/Фcos²Ф]

==> dy/dФ = 1+ 64tanФ/Ф or dy/dФ = (Ф+tanФ)/Ф

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