Answer:
B) 3
Step-by-step explanation:
add 5 to both sides, 4x=12
divide both sides by 4, x=3
Amount owed at the end of 1 year is 3640
<h3><u>Solution:</u></h3>
Given that yoko borrows $3500.
Rate of interest charged is 4% compounded each year
Need to determine amount owed at the end of 1 year.
In our case
:
Borrowed Amount that is principal P = $3500
Rate of interest r = 4%
Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1
<em><u>Formula for Amount of compounded yearly is as follows:</u></em>

Where "p" is the principal
"r" is the rate of interest
"n" is the number of years
Substituting the values in above formula we get


Hence amount owed at the end of 1 year is 3640
The answer is -6 because the square root of 36 is 6, but then you have to add the negative in front of it.
Answer:
The first equation answer is 10
And the second one 6
Step-by-step explanation:
The first equation
2/5 x +3= 2/3x +1/3
2x + 15/5 = 6x+3/9 the cress cross
9(2x + 15) = 5(6x + 3)
18x + 135 = 30x +15
135-15 = 30x - 18x
120 = 12x
120/12 =12x/12
10 = x
X =10
The second one
-2.6b +4 =0.9b - 17
-2.6b - 0.9b = - 17 - 4
-2.6b + (-0.9b) = - 17 + (-4)
-3.5b = - 21
-3.5b/-3.5 = - 21 /-3.5
B= 6