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ryzh [129]
3 years ago
11

R + (-5r) Please explain how it's done.

Mathematics
1 answer:
Lisa [10]3 years ago
7 0

Answer:

-4r

Step-by-step explanation:

r + (-5r)

1r + (-5r)

Factor out an r

r( 1 -5)

One minus 5 is negative 4.   If you have one dollar and you borrow five dollars,  how much did you borrow?  4  but that 4 is borrowed so it is negative


r (-4)

-4r



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Quadrilateral RJFT is similar to quadrilateral SYPA . JF=60 mm , AP=40 mm , and YP=25 mm . What is TF ?
Hoochie [10]
The two quadrilaterals are similar. Which means the ratios of respective sides of two quadrilaterals will be the same. 

So, for the given quadrilaterals, ratio of sides JF and TF of quadrilateral RJFT will be equal to the ratio of sides YP and AP of quadrilateral SYPA. Mathematically, we can write:

JF:TF = YP:AP \\  \\ 
 \frac{JF}{TF} = \frac{YP}{AP}  \\  \\ 
 \frac{60}{TF} = \frac{25}{40}  \\  \\ 
60* \frac{40}{25}=TF \\  \\ 
TF=96mm

So the measure of TF will be 96mm
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3 years ago
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Answer:

35

37^2 - 12^2

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6 0
3 years ago
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Zanzabum

Answer:

A

Step-by-step explanation

4 0
3 years ago
Read 2 more answers
Please anyone answer me
ollegr [7]

Let's divide the shaded region into two areas:

area 1: x = 0 ---> x = 2

ares 2: x = 2 ---> x = 4

In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.

Area 1:

A\frac{}{1}  = ∫g(x)dx =  ∫xdx =  \frac{1}{2}  {x}^{2}  | \frac{2}{0}  = 2

Area 2:

A\frac{}{2}  = ∫(g(x) - f(x))dx

= ∫(x -  {(x - 2)}^{2} )dx

=  ∫( - {x}^{2}  + 5x - 4)dx

= ( - \frac{1}{3}{x}^{3} +   \frac{5}{2} {x}^{2}  - 4x)   | \frac{4}{2}

= 2.67 - ( - 0.67) = 3.34

Therefore, the area of the shaded portion of the graph is

A = A1 + A2 = 5.34

3 0
3 years ago
Expand the expression by distributing <br> -2(-4x-7)
vova2212 [387]
-2(-4x-7)
Answer:
8x+14
6 0
3 years ago
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