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ANTONII [103]
3 years ago
6

A dog is 3 and one half

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
8 0
The height of the dog is 1 and two fifths. I use decimals, so it would be 1.4 feet tall. The owner is 3.75 times tall as the dog. We need to multiply.
1.4×3.75
5.25
The owner is 5 1/4 feet tall.
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<em>Hey</em><em>!</em><em>!</em><em>!</em><em>!</em>

<em>Here</em><em>'s</em><em> </em><em>you</em><em>r</em><em> </em><em>answer</em><em>:</em>

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<em>A</em><em>=</em><em>{</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em>,</em><em>5</em><em>}</em>

<em>B</em><em>=</em><em>{</em><em>5</em><em>,</em><em>6</em><em>,</em><em>7</em><em>,</em><em>8</em><em>}</em>

<em> </em><em>A</em><em> </em><em>U</em><em> </em><em>B</em><em>=</em><em>{</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em>,</em><em>5</em><em>}</em><em> </em><em>U</em><em> </em><em>{</em><em>5</em><em>,</em><em>6</em><em>,</em><em>7</em><em>,</em><em>8</em><em>}</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>{</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em>,</em><em>5</em><em>,</em><em>6</em><em>,</em><em>7</em><em>,</em><em>8</em><em>}</em>

<em>In</em><em> </em><em>case</em><em> </em><em>of</em><em> </em><em>Union</em><em>,</em><em>we</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>list</em><em> </em><em>all</em><em> </em><em>the</em><em> </em><em>elements</em><em> </em><em>which</em><em> </em><em>are</em><em> </em><em>present</em><em> </em><em>in</em><em> </em><em>both</em><em> </em><em>sets</em><em>.</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps.</em><em>.</em><em>.</em>

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Crank

\huge\textbf{Hey there!}

\mathbf{7\dfrac{1}{6} = 5\dfrac{2}{5} + p}

\rightarrow\mathbf{7 \dfrac{1}{6} = 5\dfrac{2}{5} + p}

\mathbf{\rightarrow p + 5\dfrac{2}{5}= 7\dfrac{1}{6}}

\mathbf{\rightarrow {p + \dfrac{27}{5}=\dfrac{43}{6}}}

\text{SUBTRACT }\rm{\dfrac{27}{5}}\text{ to BOTH SIDES}

\mathbf{p + \dfrac{27}{5} - \dfrac{27}{5} = \dfrac{43}{6}- \dfrac{27}{5}}

\text{CANCEL out: }\rm{\dfrac{27}{5} - \dfrac{27}{5}}\text{ because it gives you 0}

\text{KEEP: }\rm{\dfrac{43}{6} - \dfrac{27}{5}}\text{ because it help solve for the p-value}

\text{NEW EQUATION: }\rm{p = \dfrac{43}{6} - \dfrac{27}{5}}

\large\textsf{SIMPLIFY IT!}

\mathbf{p = \dfrac{53}{30} \approx p = 1\dfrac{23}{30}}

\huge\boxed{\textsf{Therefore, your answer is: \boxed{\mathsf{p = 1\dfrac{23}{30}}}}}\huge\checkmark

\huge\textbf{Good luck on your assignment \&}\\\huge\textbf{enjoy your day!}

~\frak{Amphitrite1040:)}

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