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3 years ago

What are the element names for the following symbols? Ni,He, Pb

Physics

2 answers:

vladimir1956 [14]3 years ago

7 0

Ni is Nickel.
He is Helium.
Pb is Lead.

Kay [80]3 years ago

6 0

Ni - Nickel
He - Helium
Pb - Lead

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Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The d

Mumz [18]

Answer:

Part a)

Purple car = Light Blue car > (Red car = Yellow Car = Blue car) > Green Car

Part b)

Purple car = Light Blue car > (Red car = Yellow Car = Blue car) > Green Car

Part c)

Purple car = Light Blue car > (Red car = Yellow Car = Blue car) > Green Car

Explanation:

Red car

mass = 1000 kg

speed = 10 m/s

Yellow car

mass = 2000 kg

speed = 5 m/s

Blue car

mass = 500 kg

speed = 20 m/s

Light Blue car

mass = 1000 kg

speed = 20 m/s

Green car

mass = 500 kg

speed = 10 m/s

Purple car

mass = 4000 kg

speed = 5 m/s

Part a)

Now we know that momentum of each car is product of mass and velocity

so we will have

Red Car

$P_1 = m v$

$P_1 = (1000)(10)$

$P_1 = 10^4 kg m/s$

Yellow Car

$P_2 = m v$

$P_2 = (2000)(5)$

$P_2 = 10^4 kg m/s$

Blue Car

$P_3 = m v$

$P_3 = (500)(20)$

$P_3 = 10^4 kg m/s$

Light Blue Car

$P_4 = m v$

$P_4 = (1000)(20)$

$P_4 = 2\times 10^4 kg m/s$

Green Car

$P_5 = m v$

$P_5 = (500)(10)$

$P_5 = 5 \times 10^3 kg m/s$

Purple Car

$P_6 = m v$

$P_6 = (4000)(5)$

$P_6 = 2\times 10^4 kg m/s$

So the momentum is given as

Purple car = Light Blue car > (Red car = Yellow Car = Blue car) > Green Car

Part b)

Impulse is given as change in momentum so here we can say that final momentum of all the cars will be zero as they all stops and hence the impulse is same as initial momentum of the car

so the order of impulse from largest to least is given as

Purple car = Light Blue car > (Red car = Yellow Car = Blue car) > Green Car

Part c)

Force is defined as rate of change in momentum

Now let say all cars will stop in same time interval

so we will have

$Force = \frac{impulse}{time}$

so we will have

force is in same order as that of impulse

so it is given as

Purple car = Light Blue car > (Red car = Yellow Car = Blue car) > Green Car

5 0

4 years ago

Read 2 more answers

In a Young's double-slit experiment, a set of parallel slits with a separation of 0.114 mm is illuminated by light having a wave

elena-14-01-66 [18.8K]

Answer:

a) 2232nm

b) 2511nm

Explanation:

a) To find the path difference Δl you use the following formula:

$\Delta l=m\lambda$

m: order of a bright fringe

λ: wavelength of light = 558nm

for m=4:

$\Delta l=(4)(558nm)=2232nm$

b) The path difference for the case of destructive interference you have:

$\Delta l=(m+\frac{1}{2})\lambda$

m: order of a dark fringe

for m=4:

$\Delta l=(4+\frac{1}{2})(558nm)=2511nm$

7 0

3 years ago

Sara went 25 m in 4 s. How fast did she go?

Angelina_Jolie [31]

She went around half a microsecond

8 0

3 years ago

Solve for v. 5 · v=25

liberstina [14]

Answer:

v= 25

Explanation:

5*5=25

4 0

3 years ago

A toboggan approaches a snowy hill moving at 11.7 m/s. The coefficients of static and kinetic friction between the snow and the

soldi70 [24.7K]

Answer:

The acceleration of the toboggan going up and down the hill is 8.85 m/s² and 3.74 m/s².

Explanation:

Given that,

Speed = 11.7 m/s

Coefficients of static friction = 0.48

Coefficients of kinetic friction = 0.34

Angle = 40.0°

(a). When the toboggan moves up hill, then

We need to calculate the acceleration

Using formula of acceleration

$a=g(\sin\theta+\mu_{k}\cos\theta)$

Put the value into the formula

$a=9.8(\sin40+0.34\times\cos40)$

$a=8.85\ m/s^2$

(b). When the toboggan moves up hill, then

We need to calculate the acceleration

Using formula of acceleration

$a=g(\sin\theta-\mu_{k}\cos\theta)$

Put the value into the formula

$a=9.8(\sin40-0.34\times\cos40)$

$a=3.74\ m/s^2$

Hence, The acceleration of the toboggan going up and down the hill is 8.85 m/s² and 3.74 m/s².

5 0

3 years ago