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leva [86]
3 years ago
7

Kinetic and

Physics
1 answer:
beks73 [17]3 years ago
5 0

Answer:

raise the board to a higher angle

Explanation:

Static friction is the force opposite to the applied force.

Static friction is dependent on the angle of inclination, it means as the angle of incline increases, the force of friction will increases as normal force will decrease.

So, if the board will be raised to a higher angle, it will increase the angle of incline and will overcome the static friction and block will be able slide.

Hence, the correct option is "raise the board to a higher angle".

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Think about the force that causes a planet to orbit the Sun and the direction of this
Evgesh-ka [11]

Answer:

1) For the swung puck tied to the string that has a mass m₁ and having another mass m₂ attached to the string that passes through a hole in the table, such that m₂ > m₁

The swung puck rotating on the table is kept in the circular motion on the table by the centripetal force acting towards the center of its rotation along the string, which is given by the amount the weight of m₂ exceeds m₁, in the same way a planet moving around the Sun is kept in its orbit by the gravitational attraction between the planet and the Sun.

2) i) The forces acting on the puck are;

a) The centripetal force in the string, acting inward, towards the center of rotation provided by the weight of m₂

b) The centrifugal force of the puck, acting outward, tending to continue its motion in a straight line

ii) The forces acting on the planet are;

a) The force of gravitational attraction between the planet and the Sun, acting towards the Sun, such that, the planet revolves around the Sun

b) The centrifugal force of the planet, acting outward, tending to move in a linear or straight path

Explanation:

8 0
3 years ago
Bird man is flying horizontally at a speed of 33m/s and a height of 86m. Bird man releases a turd directly above the start of th
Aliun [14]

Answer:

2838

Explanation:

8 0
3 years ago
A large storage tank, open to the atmosphere at the top and filled with water, develops a small hole in its side at a point 15.6
VladimirAG [237]

To solve this problem it is necessary to take into account the kinematic equations of motion and the change that exists in the volume flow.

By definition the change in speed is given by

v_f^2-v_i^2 = 2ax

Where,

x= distance

v_f =final velocity

v_i =initial velocity

a = acceleration

On the other hand we know that the flow of a fluid is given by

\dot{V} = Av

Where,

A = Area

v = Velocity

PART A )

Applying this equation to the previously given values we have to

v_f^2-v_i^2 = 2ax

v_f^2-0 = 2*(9.8)(15.6)

v_f^2=305.76

v_f = 17.48

Therefore the velocity of the water leaving the hole is 17.48m/s

PART B )

In the case of the hole we take the area of a circle, therefore replacing in the flow equation we have to,

\dot{V} = \pi r^2 v

r = \sqrt{\frac{\dot{V}}{\pi v}}

r = \sqrt{\frac{3*10^{-3}*\frac{1}{60}}{\pi (17.48)}

r = \sqrt{9.10*10^{-7}}

r = 0.54*10^{-4}

The diameter is 2 times the radius, then is 1.91*10^{-3}m or 1.91mm

<em>Note: The rate flow was converted from minutes to seconds.</em>

8 0
3 years ago
What is the energy of a 4kg apple that is sitting on a 2 m high tree branch?
miv72 [106K]

78.4 joules is the energy of a 4 kg apple that is sitting on a 2 m high tree branch.

<u>Explanation: </u>

When an apple falls to the ground from a tree, its positional energy (stored as potential gravitational energy) turns into kinetic energy, during a fall. Chemical potential energy is chemical energy because it is food and potential energy as it can still have ability to move. So, in the given case, kinetic energy is zero.

To find potential energy, the formula would be

             \text { potential energy }(P . E)=m \times g \times h

Where, given

m – Mass – 4 kg

g-\text { Earth'sgravity }-9.8 \mathrm{m} / \mathrm{s}^{2} (Known value)

h – Height -  2 m

Substitute these values, we get

                  P . E=4 \times 9.8 \times 2=78.4 \text { joules }

8 0
3 years ago
the electric field midway between two equal but opposite point charges is 573 n/c , and the distance between the charges is 16.0
saveliy_v [14]

The electric potential  between the two charges is 91.68 V.

<h3>Electric potential between the two charges</h3>

The electric potential  between the two charges is calculated as follows;

V = Ed

where;

  • V is electric potential
  • E is electric field
  • d is the distance of the charge

Substitute the given parameters and solve for electric potential,

V = 573 N/c x 0.16 m

V = 91.68 V

Thus, the electric potential  between the two charges is 91.68 V.

Learn more about electric potential here: brainly.com/question/26978411

#SPJ4

4 0
1 year ago
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