The velocity of B after elastic collision is 3.45m/s
This type of collision is an elastic collision and we can use a formula to solve this problem.
<h3>Elastic Collision</h3>

The data given are;
- m1 = 281kg
- u1 = 2.82m/s
- m2 = 209kg
- u2 = -1.72m/s
- v1 = ?
Let's substitute the values into the equation.

From the calculation above, the final velocity of the car B after elastic collision is 3.45m/s.
Learn more about elastic collision here;
brainly.com/question/7694106
Answer:
O- to track how fast a heart beats
Explanation:
The forces are net forces. I think this is correct.
Answer:
4180 N
Explanation:
In order to keep the truck balanced and stationary, the force of friction on the truck must be equal to the component of the weight of the truck acting parallel to the slope.
The component of the weight of the truck acting parallel to the slope is:

where
m = 3500 kg is the mass of the truck
g = 9.8 m/s^2 is the acceleration of gravity
is the angle of the slope
Therefore, the force of friction must be equal to

Answer:
P = 23.32 W
Explanation:
In series
equivalent Resistance
R(eq)=R+R=2R
In parallel equivalent resistance
R(eq) = R*R/(R+R) =R/2
since.
power
P=V² / R
in series
⇒V = √(P*R)
=√(5.83*2R
)
=√(11.66R)
in parallel
P = V² / R(eq)
=(√(11.66R)²) / (R/2)
P=11.66 * R * 2/R
P = 23.32 W