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Veseljchak [2.6K]
2 years ago
6

Please help with this...thank you:D

Mathematics
1 answer:
Crank2 years ago
6 0
Relationship 1: y1 = x + 3
Relationship 2: y2 = 3x^2
Relationship 3: y3 = 3^x
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Please help asap. 55 points
atroni [7]
The answer would be B. Using the foil method to check, the two k's equal k^2, then the k and -f would equal -fk, plus the 2fk would equal a positive fk. Lastly, the 2f and -f would equal -2f^2.
5 0
2 years ago
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Please help! Due in 1 hour
Ket [755]
If the questions are asking where the two equations meet the answer is (1,1)
3 0
2 years ago
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50points+brainliest for the one who solved this.It's not a homework but I am curious​
4vir4ik [10]

Answer:

  • 1/xy

Step-by-step explanation:

<u>Simplify the numerator:</u>

  • (2x - y)/(2x + y) + (2x + y)/(3y - 6x) + 8xy/(12x² - 3y²) =
  • (2x - y)/(2x + y) - (2x + y)/3(2x - y) + 8xy/3(2x + y)(2x - y) =
  • [3(2x - y)² - (2x + y)² + 8xy] / [3(2x + y)(2x - y)] =
  • [12x² - 12xy + 3y² - 4x² - 4xy - y² + 8xy] / [3(2x + y)(2x - y)] =
  • [8x² - 8xy + 2y²] / [3(2x + y)(2x - y)] =
  • 2{2x - y)² / [3(2x + y)(2x - y)] =
  • 2(2x - y) / [3(2x + y)]

<u>Simplify the denominator:</u>

  • (4x²y - 2xy²) / (6x + 3y) =
  • 2xy(2x - y) / [3(2x + y)]

<u>Now simplify the remainder of the expression:</u>

  • 2(2x - y) / [3(2x + y)] × [3(2x + y)]/[2xy(2x - y}] =
  • 1/xy
4 0
2 years ago
Consider triangle GHJ.
bulgar [2K]

we know that

<u>Applying the Pythagorean Theorem</u>

JG^{2} =HJ^{2}+HG^{2}

solve for HJ

HJ^{2}=JG^{2}-HG^{2}

in this problem we have

JG=10\ units\\ HG= 5\ units

Substitute the values in the formula above

HJ^{2}=10^{2}-5^{2}

HJ^{2}=100-25

HJ^{2}=75

HJ=\sqrt{75}=5\sqrt{3} \ units

therefore

<u>the answer is the option</u>

B. 5 sq. root 3 units

5 0
3 years ago
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Please help , and explain because i keep getting it wrong and it’s getting on my nerves
skad [1K]

Answer:

Olga's mistake: She did not multiply \frac{1}{4} and \frac{1}{3} in the beginning

Step-by-step explanation:

The main problem is that when a number is outside of the parentheses on the left side, then you have to multiply that number, in this case \frac{1}{4}, by both numbers in the parentheses. After that, continue solving the problem as you usually would. Hope this helped!

8 0
2 years ago
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