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2 years ago

Please help with this...thank you:D

Mathematics

1 answer:

Crank2 years ago

6 0

Relationship 1: y1 = x + 3
Relationship 2: y2 = 3x^2
Relationship 3: y3 = 3^x

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A and B are partners sharing profit and loss in the ratio of 3:2. A new partner C is admitted and 1/4 share off profit is given.

Gre4nikov [31]

Answer:

Correct option is: 9:6:5

Step-by-step explanation:

I'm not sure but hope it helps.

6 0

2 years ago

Assume that women's heights are normally distributed with a mean given by mu equals 62.5 in,and a standard deviation given by

Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with

$\mu$ = 62.5 in

$\sigma$ = 2.2 in

the normal probability density function is given by

$f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}$ , then

(a) $P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx$ = 0.5899

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking $P(\bar{X} < 63)$ where n = 37. $\bar{X}$ is normally distributed with mean 62.5 in and standard deviation $2.2/\sqrt{37}$ . So, the probability density function is given by

$g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}$ , and

$P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx$ = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0

2 years ago

Find the speed of a race car if it travels 5 miles in 2 minutes and 30 seconds

Tomtit [17]

You first convert the 2 minutes and 30 seconds to 150 seconds.

Then, you take the 150s÷5m to get the number of seconds per mile.

The answer is 30s/m

4 0

3 years ago

Use a ratio to compare this quantity 25mm : 2cm

Tema [17]

5:4 i’m not quite sure but i think it would be 5:4

4 0

2 years ago

Perimeter of 316 and 67 m

storchak [24]

Answer:

383 m

Step-by-step explanation: