Answer:
Statement, Reason
Given segment RV = segment TU, Given
m∠R = m∠T, Given
Segment RS ≅ segment ST, Base angles theorem
ΔRSV ≅ ΔTSU, SAS rule of congruency
Segment SV ≅ segment SU, CPCTC
VU ≅ UV, Reflexive property
RU = RV + VU, TV = TU + UV, Addition of segments
RV + VU ≅ TU + UV, Addition property of equality
RU ≅ TV, Transitive property of addition
ΔRSU ≅ ΔTSV, SSS rule of congruency
Step-by-step explanation:
Where:
SAS- Side Angle Side
CPCTC -Congruent Parts of Congruent Triangles are Congruent
SSS -Side Side Side
The fundamental theorem of algebra states that a polynomial with degree n has at most n solutions. The "at most" depends on the fact that the solutions might not all be real number.
In fact, if you use complex number, then a polynomial with degree n has exactly n roots.
So, in particular, a third-degree polynomial can have at most 3 roots.
In fact, in general, if the polynomial
has solutions
, then you can factor it as

So, a third-degree polynomial can't have 4 (or more) solutions, because otherwise you could write it as

But this is a fourth-degree polynomial.
Answer:
correct answer is 406/25+a10
Step-by-step explanation:
Answer: t=33
Step-by-step explanation:
M - 30 = 10
so the number has to be 10 more than 30.
30+ 10 = m
m = 40