18.90? I believe would be the answer . Let's see if someone else responds
Answer:
(-20,0) (0,-4)
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that tank has the shape of inverted circular cone
Height = 10 feet and radius = 4 feet
After water pumped out height = 5 ft
Hence volume of water pumped out = 
Here we have r/h is constant always
Hence 
Substitute to get volume of water pumped out = 
Mass of water = density x volume = 
Work done = force x displacement
= mass x accen x displacement
Here acceleration = gravity = 32.2 ft/sec^2
Displaement = height reduced = 5 ft
W=2912(32.2)(5)\pi =468832\pi foot -pound
Answer:
The answer is -8x-10
Step-by-step explanation:
-4(2x+3)-2
you will use the -4 to open the bracket
-8x-12-2
-8x-10
Answer:
28.3 units (3 s.f.)
Step-by-step explanation:

Using the formula above,
distance
![= \sqrt{[6 - ( - 22)]^{2} + (16 - 12) {}^{2} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%7B%5B6%20-%20%28%20-%2022%29%5D%5E%7B2%7D%20%20%2B%20%2816%20-%2012%29%20%7B%7D%5E%7B2%7D%20%7D%20)




= 28.3 units (3s.f.)