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Sonja [21]
3 years ago
5

A car has a 16-gallon fuel tank. When driven on a highway, it has a gas mileage of 30 miles per gallon. The gas mileage (also ca

lled "fuel efficiency") tells us the number of miles the car can travel for a particular amount of fuel (one gallon of gasoline, in this case). After filling the gas tank, the driver got on a highway and drove for a while.
How many miles has the car traveled if it has the following amounts of gas left in the tank (15 galllons)?
Mathematics
2 answers:
Darya [45]3 years ago
6 0

Answer: 10

Step-by-step explanation:

ale4655 [162]3 years ago
4 0

Answer:

30

Step-by-step explanation:

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What is 18.890 rounded to the nearest hundred
bagirrra123 [75]
18.90? I believe would be the answer . Let's see if someone else responds
3 0
3 years ago
Help please! anything is appreciated, giving brainliested:)
Vaselesa [24]

Answer:

(-20,0) (0,-4)

Step-by-step explanation:

4 0
3 years ago
A tank has the shape of an inverted circular cone (point at the bottom) with height 10 feet and radius 4 feet. The tank is full
german

Answer:

Step-by-step explanation:

Given that tank has the shape of inverted circular cone

Height = 10 feet and radius =  4 feet

After water pumped out height = 5 ft

Hence volume of water pumped out = \frac{1}{3} \pi R^2 h-\frac{1}{3} \pi r^2 h'

Here we have r/h is constant always

Hence \frac{r}{h'} =\frac{R}{h} \\r=Rh'/h = 4(5)/10 = 2

Substitute to get volume of water pumped out = \frac{1}{3} \pi (10*16-4*5)=\frac{140\pi}{3}

Mass of water = density x volume = 62.4(\frac{140\pi}{3})\\= 2912\pi lbs

Work done = force x displacement

= mass x accen x displacement

Here acceleration = gravity = 32.2 ft/sec^2

Displaement = height reduced = 5 ft

W=2912(32.2)(5)\pi =468832\pi foot -pound

6 0
3 years ago
-4(2x+3)-2 <br> Show and explain work <br> (Distributive property)
Alexeev081 [22]

Answer:

The answer is -8x-10

Step-by-step explanation:

-4(2x+3)-2

you will use the -4 to open the bracket

-8x-12-2

-8x-10

5 0
4 years ago
Find the distance between the pair of points. (6,16) and (-22,12)​
bonufazy [111]

Answer:

28.3 units (3 s.f.)

Step-by-step explanation:

\boxed{distance \: between \: 2 \: points =  \sqrt{ {(x1 - x2)}^{2}  +  {(y1 - y2)}^{2} } }

Using the formula above,

distance

=  \sqrt{[6 - ( - 22)]^{2}  + (16 - 12) {}^{2} }

=  \sqrt{(6 + 22) {}^{2} +  {4}^{2}  }

=  \sqrt{ {28}^{2} + 16 }

=  \sqrt{784 + 16}

=  \sqrt{800}

= 28.3 units (3s.f.)

6 0
3 years ago
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