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lilavasa [31]
3 years ago
9

2. Alexis bought four jars of pickles. The total mass of the four jars was 12 kilograms. What is the mass, in grams, of each jar

of pickles? Anwsers:​

Mathematics
2 answers:
Tom [10]3 years ago
8 0

Answer:

it´s 3,000

Step-by-step explanation:

Pie3 years ago
3 0
The answer is J 3,000grams
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Ed bought 3 liters of water, 2,750 milliliters of sports drinks, and 2.25 liters of juice. For numbers 4a-4e, select True or Fal
Naily [24]
<span>4a) 1000 milliliters = 1 liter, thus 3 liters = 3 x 1000 = 3000 milliliters.
Thus Ed bought 3000 - 2750 = 250 more water than sports drink.
Therefore, Ed bought 250 milliliters more water than sports drink is True.

4b) Ed bought 3 - 2.25 = 0.75 more water than juice.
Therefore, Ed bought 1.25 liters more water than juice is False.

4c) Ed bought 2.25 liters = 2.25 x 1000 = 2250 milliliters of juice.
Thus, Ed bought 2750 - 2250 = 500 more sports drink than juice.
Therefore, Ed bought 50 milliliters more sports drink than juice is False.

4d) Ed bought 2750 milliliters = 2750 / 1000 = 2.75 liters of sports drink.
Ed bought 2.75 - 2.25 = 0.5 liters more sports drink than juice.
Ed bought 0.5 liter more of sports drink than juice is True.

4e) Ed bought 3000 milliliters of water and 2250 milliliters of juice.
Ed bought 3000 - 2250 = 750 more milliliters of water than juice.
Therefore, Ed bought 75 milliliters more water than juice is False.</span>
8 0
4 years ago
<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%20%5Cinfty%20%20%5Cfrac%7B%20%5Csqrt%5B%20%20%5Cscriptsize%5Cphi%
Rasek [7]

With ϕ ≈ 1.61803 the golden ratio, we have 1/ϕ = ϕ - 1, so that

I = \displaystyle \int_0^\infty \frac{\sqrt[\phi]{x} \tan^{-1}(x)}{(1+x^\phi)^2} \, dx = \int_0^\infty \frac{x^{\phi-1} \tan^{-1}(x)}{x (1+x^\phi)^2} \, dx

Replace x \to x^{\frac1\phi} = x^{\phi-1} :

I = \displaystyle \frac1\phi \int_0^\infty \frac{\tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx

Split the integral at x = 1. For the integral over [1, ∞), substitute x \to \frac1x :

\displaystyle \int_1^\infty \frac{\tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx = \int_0^1 \frac{\tan^{-1}(x^{1-\phi})}{\left(1+\frac1x\right)^2} \frac{dx}{x^2} = \int_0^1 \frac{\pi2 - \tan^{-1}(x^{\phi-1})}{(1+x)^2} \, dx

The integrals involving tan⁻¹ disappear, and we're left with

I = \displaystyle \frac\pi{2\phi} \int_0^1 \frac{dx}{(1+x)^2} = \boxed{\frac\pi{4\phi}}

8 0
2 years ago
1.5 meters equal how many cm
hram777 [196]
1 meter = 100 cm. So 1 1/2 meters = 150 cm.
3 0
3 years ago
Read 2 more answers
Find the area of the triangle base=8cm height= 5cm
mario62 [17]
Area= 1/2 base x height

Area= 1/2 8x5

Area= 40/2

Area= 20cm^2
8 0
3 years ago
Is anybody better at this then I am ?
lbvjy [14]

Answer:

hmmm

Step-by-step explanation:

8 0
3 years ago
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