Can you simplify (9c^8)^1/2
1 answer:
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Keywords:
<em>equation, variable, clear, round, centesima, neperian logarithm, exponential </em>
For this case we have the following equation , from which we must clear the value of the variable "x" and round to the nearest hundredth. To do this, we must apply properties of neperian and exponential logarithms. By definition:
So:
We apply Neperian logarithm to both sides:
We divide between "3" both sides of the equation:
Rounding out the nearest hundredth we have:
Answer:
Let
x--------> <span>the rectangle's length
y-------> </span><span>the rectangle's width
we now that
Area of rectangle=x*y
Area=256 cm</span>²
<span>256=x*y-------> equation 1
y=4x-48------> y=4x-48------> equation 2
substitute equation 2 in equation 1
256=x*[4x-48]-----> 256=4x</span>²-48x
4x²-48x-256=0
<span>
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
x=16 cm
y=4x-48----> y=4*16-48-----> y=16 cm
is a square
the answer is
</span>the rectangle's length is 16 cm
x--------> <span>the rectangle's length
y-------> </span><span>the rectangle's width
we now that
Area of rectangle=x*y
Area=256 cm</span>²
<span>256=x*y-------> equation 1
y=4x-48------> y=4x-48------> equation 2
substitute equation 2 in equation 1
256=x*[4x-48]-----> 256=4x</span>²-48x
4x²-48x-256=0
<span>
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
x=16 cm
y=4x-48----> y=4*16-48-----> y=16 cm
is a square
the answer is
</span>the rectangle's length is 16 cm