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2 years ago

Can you give an example of equations when you are given the constant of proportionality?

Mathematics

1 answer:

aleksandr82 [10.1K]2 years ago

6 0

Example:
Proportionality=1
5=5x
Divide both sides by 5 , and you get 1=x,
so the proportionality is 1

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EXERCISE 3.4

Lisa [10]

Answer:

I think it's C. sjisebd ddhisuaja. usually get ebe.

7 0

2 years ago

Printer A can print 30 pages per minute. Printer B can print 40 pages per minute. Printer B begins printing 3 minutes after Prin

anzhelika [568]

Printer A prints for 10 minutes, so prints

... (30 pages/minute)×(10 minutes) = 300 pages

Printer B prints for 7 minutes, so prints

... (40 pages/minute)×(7 minutes) = 280 pages

At the end of 10 minutes, the two printers will have printed

... 300 pages + 280 pages = 580 pages

8 0

2 years ago

Find the 2th term of the expansion of (a-b)^4.

vladimir1956 [14]

The second term of the expansion is $-4a^3b$ .

Solution:

Given expression:

$(a-b)^4$

To find the second term of the expansion.

$(a-b)^4$

Using Binomial theorem,

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here, a = a and b = –b

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

Substitute i = 0, we get

$$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4$

Substitute i = 1, we get

$$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b$

Substitute i = 2, we get

$$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}$

Substitute i = 3, we get

$$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}$

Substitute i = 4, we get

$$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}$

Therefore,

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

$=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}$ $=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}$

Hence the second term of the expansion is $-4a^3b$ .

3 0

2 years ago

The radius of a circular park is 114 yd. To the nearest yard, what is the circumference of the park?

adell [148]

circumference = 2 x pi x r

using 3.14 for pi

2 x3.14x114=715.92

round to 716 yards

6 0

3 years ago

Read 2 more answers

P(A)=0.45, P(A∩B)=0.15 and P(B\A)=0.25 what is the value of P(A\B)

Fiesta28 [93]

Answer:

0.35? That is correct?

7 0

2 years ago