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3 years ago

What's the midpoint between 1000 and 2000?

Mathematics

1 answer:

Free_Kalibri [48]3 years ago

5 0

The midpoint between 1000 and 2000 is 1500

1. Add them together

2. Divide them by two

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PLZ HELP ME ASAP

ludmilkaskok [199]

The height to width ratio of the Indian Flag is 2:3.

So, for every 2 (inches, meters, whatever) of height
there should be 3 of width.

Indian flag Sentence Examples:

1. If we made the flag 20 inches high, it should be 30 inches wide.

2. If we made the flag 40 cm high, it should be 60 cm wide (which is still in the ratio 2:3).

I hope this helps.

3 0

3 years ago

(v+6)(v-6)=0 this is algebra 1 and factoring

Novay_Z [31]

First step to solve (v+6)(v-6)=0 is to use FOIL and dd the multiplication
v^2-6v+6v-36=0
v^2-36=0\ or v^2=36
we need to take the square root from both sides so
v=6 and v=-6
<span>v = {-6, 6}</span>

4 0

4 years ago

Read 2 more answers

There are 8 rows and 8 columns, or 64 squares

lawyer [7]

Complete Question:

There are 8 rows and 8 columns, or 64 squares on a chessboard.

Suppose you place 1 penny on Row 1 Column A,

2 pennies on Row 1 Column B,

4 pennies on Row 1 Column C, and so on …

Determine the number of pennies in Row 1

Determine the number of pennies on the entire chessboard?

Answer:

255 in the first row

18,446,744,073,709,551,615 in the entire board

Step-by-step explanation:

Given

$Rows = 8$

$Columns = 8$

Solving (a): Number of pennies in first row

The question is an illustration of geometric sequence which follows

$1,2,4....$

Where

$a =1$ --- The first term

Calculate the common ratio, r

$r = \frac{T_2}{T_1} = \frac{4}{2} = 2$

The number of pennies in the first row will be calculated using sum of n terms of a GP.

$S_n = \frac{a(r^n - 1)}{n - 1}$

Since, the first row has 8 columns, then

$n = 8$

Substitute 8 for n, 2 for r and 1 for a in $S_n = \frac{a(r^n - 1)}{r - 1}$

$S_8 = \frac{1 * (2^8 - 1)}{2 - 1}$

$S_8 = \frac{1 * (256 - 1)}{1}$

$S_8 = \frac{1 * 255}{1}$

$S_8 = 255$

Solving (b): The entire board has 64 cells.

So:

$n = 64$

Substitute 64 for n, 2 for r and 1 for a in $S_n = \frac{a(r^n - 1)}{r - 1}$

$S_{64} = \frac{1 * (2^{64} - 1)}{2 -1}$

$S_{64} = \frac{(2^{64} - 1)}{1}$

$S_{64} = \frac{(18,446,744,073,709,551,616 - 1)}{1}$

$S_{64} = \frac{18,446,744,073,709,551,615}{1}$

$S_{64} = 18,446,744,073,709,551,615$

5 0

3 years ago

Find all real values of t that satisfy the equation t^2 = 324. If you find more than one, then list your values in increasing or

vredina [299]

Answer:

t = -18, 18

Step-by-step explanation:

Take the square root of both sides of the equation.

... t = ±√324 = ±18

4 0

4 years ago

Your family went out to eat. The total bill was

babunello [35]

I’m pretty sure it is somewhere around 10.275. Because if you take 15% of 68.50 that is what comes up. I’m not sure if this is right but I hope it helps

7 0

3 years ago