Cos x = -12/13
sin x = -sqrt(13^2 - 12^2) / 13 = -5/13
tan x = 5/12
tan x/2 = (1 - cos x) / sin x = 1 - (-12/13) / -5/13 = 25/13 * -13/5 = -5
2sin^2 x/2 = 1 - cos x = 1 - (-12/13) = 25/13
sin^2 x/2 = 25/13 / 2 = 25/26
sin x/2 = 5/√26
sin x/2 / cos x/2 = tan x/2
cos x/2 = sin x/2 / tan x/2 = 5/√26 / -5 = -1/√26
sin x/2 = 5/√26
cos x/2 = -1/√26
tan x/2 = -5
<span>To find the beginning position, we need to know how many feet the climber has ascended in the 6-hour time frame. At the rate of 800 feet per hour, this would total to 4,800 feet in 6 hours (800 * 6). Subtracting this amount from the final position would give the elevation at the beginning of the ascent: (11600 - 4800) = 6,800 feet above sea level to begin.</span>
Answer:
3y = 2x + 24
Step-by-step explanation:
The correct question is as follows;
Write an equation of the line that goes through the point (6, 12) and has a slope of 2/3
Solution
Here, we have a point and a slope, and we want to write the equation of the line
The method we shall use here is the point slope method
Mathematically, that will be;
y-y1 = m(x-x1)
(x1,y1) = (6,12)
m = 2/3
y-12 = 2/3(x-6)
3(y-12) = 2(x-6)
3y-36 = 2x - 12
3y = 2x -12 + 36
3y = 2x + 24
I needed help with that too
Http://www.pierce.ctc.edu/staff/dlippman/mathinsociety/Finance1.0.pdf I think this will help
