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olasank [31]
3 years ago
12

What is the solution to 5 over 6 x minus one-third greater-than 1 and one-third?

Mathematics
1 answer:
inna [77]3 years ago
4 0

The solution to the inequality is x > 2.

Step-by-step explanation:

According to given statement;

The inequality is;

\frac{5}{6}x-\frac{1}{3}>1\frac{1}{3}

Solving the inequality;

\frac{5}{6}x-\frac{1}{3}>\frac{4}{3}

Adding 1/3 on both sides

\frac{5}{6}x-\frac{1}{3}+\frac{1}{3}>\frac{4}{3}+\frac{1}{3}\\\\\frac{5}{6}x>\frac{4+1}{3}\\\\\frac{5}{6}x>\frac{5}{3}

Multiplying both sides by \frac{6}{5}

\frac{6}{5}*\frac{5}{6}x>\frac{5}{3}*\frac{6}{5}\\x>2

Therefore;

The solution to the inequality is x > 2.

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I used the generic rectangle/diamond method, although the quadratic formula would work just as well with a=3, b=11, c=6.  Put that into the quadratic formula\frac{-b+/- \sqrt{b ^{2}-4ac } }{2a} to get that your factors are x = -2/3 and -3.  Putting those into factorization form you get the 2 factors as (3x+2)(x+3)

8 0
4 years ago
How would you choose to reduce the system shown to a 2 × 2? Explain why you would choose this approach. –3x + y – 2z = 10 (1) 5x
gladu [14]
-3x + y - 2z = 10      |* -1
3x  -  y  +2z = -10
5x  -2y -2z =  12 
---------------------------      I add these equations   term by term 
8x  - 3y  = 2 

-3x  + y - 2z =10                       ⇒  -3x  + y   - 2z =10
x     -y    +z = 23         | *2              2x   - 2y + 2z = 46
                                                   -----------------------------  I add these eq.
                                                       -x  -y  = 56

8x  - 3y  = 2 
-x   -y    = 56

this is the system after i reduce it ( it has only two variables x and y)




4 0
3 years ago
Read 2 more answers
Find the common ratio for the sequence: <br><br> 24, 18, 27/2, 81/8 , . . . .
marissa [1.9K]

Answer:

as we know,

common ratio=t2/t1

= 18/24

=3/4

8 0
3 years ago
Find the of fish food cubes it takes to fill the large box
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??????? Context please
5 0
3 years ago
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Two planes just took off from Charlotte NC. The first plane is traveling 1.5 times as fast as the second plane. After traveling
Ksju [112]

Givens

Slower plane

r = r

t = 2.5 hours

d = d

Faster Plane

r_faster = 1.5 * r

t = 2.5 hours

d1 = d + 127.5

The  time is the same for both

t = d/r

d1/r1 = d/r

(d+ 127.5)/1.5r = d/r   Multiply each side by r

(d + 127.5)/1.5 = d       Multiply both sides by 1.5

d + 127.5 = 1.5d          Subtract d from both sides.

127.5 = 1.5d - d    

127.5 = 0.5d              Divide by 0.5

127.5 / 0.5 = d

255 = d

Now you can go back and figure out the rates.

First find d1

d1 = d + 127.5

d1 = 255 + 127.5

d1 = 382.5

<em><u>Rate of the slower plane</u></em>

d = 255

t = 2.5 hours

r = d/t

r = 255/2.5

r = 102 miles per hour.

<em><u>Faster plane</u></em>

d1 = 382.5 miles

t = 2.5 hours

r1 = d/t

r1 = 382.5/2.5 = 153 miles per hour.


5 0
3 years ago
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