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Help, please! I need these two answered asap !
1 answer:
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1. It's all about pattern matching, as a lot of math is.
Letter A corresponds to letter J, as both are first in the names of their respective triangles.
Letter B corresponds to letter K, as both are second in the triangle names. Likewise, letter C corresponds to letter L, as both are last.
Realizing this, it should not be too much of a stretch to see
∠B ⇒ ∠K
∠C ⇒ ∠L
AC ⇒ JL
BC ⇒ KL
2. Same deal. Match the patterns. Here, you're counting rings in the angle marks.
1 ⇒ 1, so A ⇒ R
2 ⇒ 2, so B ⇒ Q
since the figures are reportedly similar, you can continue in the same order to finish.
ABCD ~ RQPS
3. The marked triangles cannot be similar. There are a number of ways to figure this. Basically, you want the ratios of sides to be the same for any similar triangles.
Here, you can eliminate the marked ones because the short side is too short relative to the others. (The average of the other two sides is double the short side in the similar triangles.)
Letter A corresponds to letter J, as both are first in the names of their respective triangles.
Letter B corresponds to letter K, as both are second in the triangle names. Likewise, letter C corresponds to letter L, as both are last.
Realizing this, it should not be too much of a stretch to see
∠B ⇒ ∠K
∠C ⇒ ∠L
AC ⇒ JL
BC ⇒ KL
2. Same deal. Match the patterns. Here, you're counting rings in the angle marks.
1 ⇒ 1, so A ⇒ R
2 ⇒ 2, so B ⇒ Q
since the figures are reportedly similar, you can continue in the same order to finish.
ABCD ~ RQPS
3. The marked triangles cannot be similar. There are a number of ways to figure this. Basically, you want the ratios of sides to be the same for any similar triangles.
Here, you can eliminate the marked ones because the short side is too short relative to the others. (The average of the other two sides is double the short side in the similar triangles.)
Answer:
The equation of line perpendicular to given line equation and passing through point (4,3) is y = 3 x - 9 .
Step-by-step explanation:
Given as :
The given equation of one line = y = x + 5
∵ Equation of line in slope-intercept form is written as
y = m x + c
where m is the slope of line
And c is the intercept of y
Now, Comparing given line equation with standard slope intercept line equation
∴ m =
Slope of this line = m =
Now, another line is perpendicular to the given line
For perpendicular lines , the products of slope of lines = - 1
Let the slope of another line = M
So, from perpendicular lines condition
m × M = - 1
∴ M =
I.e M =
So, M = 3
∴ The slope of other line = M = 3 , and the line passing through point (4,3)
Now, Again
The equation of line in slope-intercept form
I.e y = M x + c
Now, satisfying the points on line
So, 3 = 3 × 4 + c
Or, 3 = 12 + c
∴ c = 3 - 12
i.e c = - 9
or, The other line equation = y = 3 x - 9
Hence, The equation of line perpendicular to given line equation and passing through point (4,3) is y = 3 x - 9 . Answer