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kirill [66]
2 years ago
9

Who can help me wit algebra 9th grade?

Mathematics
1 answer:
Inessa05 [86]2 years ago
5 0

Answer:

Meee :)

Step-by-step explanation:

what do you need help with?

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Samuel bought a cement mixer for $54,205. The value of the cement mixer depreciated at a constant rate per year. The table shows
Paul [167]

The value of cement mixer after t year is f(t) = 54,205(0. 87)^{t}

Given to us

The value of cement mixer when bought, P= $ 54,205

the value of cement mixer after 1 year, P_1=   $ 47,158. 35

the value of cement mixer after 2 year,P_2=  $ 41,027. 76

To find out depreciation we can use the formula for depreciation,

P_n= P(1-r)^n\\where,\\P_n= Value\ of\ asset\ after\ n\ year\\P= Value\ of\ asset\ when\ bought\\r= rate\ of\ depreciation\\n= number\ of\ years

By putting the value, in the formula we get,

P_1= P(1-r)^n\\\\47,158.35= 54,205\times (1-r)^1\\\\\dfrac{47,158.35}{54,205} = (1-r)\\\\0.87=1-r\\\\r=0.13

Therefore, putting the value of r and P in depreciation formula for t years we get,

P_n= P(1-r)^n

f(t) = 54,205(0. 87)^{t}

Hence, the value of cement mixer after t year is f(t) = 54,205(0. 87)^{t}.

To know more visit:

brainly.com/question/3023490

8 0
2 years ago
8. myles had 103 coins in a jar - all nickels, dimes, and quarters. if the total value of the coins is $15
Ivanshal [37]

If the total value of the coins is $15. The number of each type of coin is: 31 quarters, 72 dimes.

<h3>Number of each type of coin</h3>

Let D = number of dimes

Let Q = the number of quarters

Equations

d + q = 103

0.10d + 0.25q = 15  

d = 103 -q

0.10(103 -q) + 0.25q = 15

10.3 - 0.10q + 0.25q = 15

0.15q = 4.7

q=4.7/0.15

q=31 quarters

Substitute q into second equation

D+31=103

D=72 dimes

Therefore the number of each type of coin is: 31 quarters, 72 dimes.

Learn more number of each coin here:brainly.com/question/13934075

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5 0
2 years ago
There are 20 triangles and 8 circles. What is the simplest ratio of circles to total shapes?
Rudik [331]

Answer:

5 to 2

Step-by-step explanation:

You can simplify both 20 and 8 by 4.

20/4 = 5

8/4 = 2

3 0
3 years ago
How can △WXY be mapped to △MNQ?
Alexeev081 [22]
The answer is : 2)line segment wy
8 0
3 years ago
In a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of th
11111nata11111 [884]

Answer:

Required probability is 0.784 .

Step-by-step explanation:

We are given that in a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of the students passed both exams.

Let Probability that the students passed the first exam = P(F) = 0.74

     Probability that the students passed the second exam = P(S) = 0.72

     Probability that the students passed both exams = P(F \bigcap S) = 0.58

Now, if the student passed the first exam, probability that he passed the second exam is given by the conditional probability of P(S/F) ;

As we know that conditional probability, P(A/B) = \frac{P(A\bigcap B)}{P(B) }

Similarly, P(S/F) = \frac{P(S\bigcap F)}{P(F) } = \frac{P(F\bigcap S)}{P(F) }  {As P(F \bigcap S) is same as P(S \bigcap F) }

                          = \frac{0.58}{0.74} = 0.784

Therefore, probability that he passed the second exam is 0.784 .

5 0
3 years ago
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