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Anton [14]
3 years ago
7

Could someone help me please ?

Mathematics
1 answer:
jeyben [28]3 years ago
5 0

Answer: 12.66

Step-by-step explanation:

Use pytagoras to find CB

AB= 6 cm

CA=12 cm

CB²=CA²-AB²

CB²=12²-6²

CB²=144-36

CB=√108

CB=6√3

Using formula for sinα=CB/CD

α=55°

sin55°=6√3/CD

CD=6√3/sin55°

CD= 6*1.73/0.82=10.38/0.82=12.66

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Sphinxa [80]

Answer:

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Step-by-step explanation:

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please give me a brainiest

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3 years ago
Find the volume of the solid generated when R​ (shaded region) is revolved about the given line. x=6−3sec y​, x=6​, y= π 3​, and
Dmitrij [34]

Answer:

V=9\pi\sqrt{3}

Step-by-step explanation:

In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).

The formula we will use for this problem is the following:

V=\int\limits^b_a {\pi r^{2}} \, dy

where:

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b=\frac{\pi}{3}

so the volume becomes:

V=\int\limits^\frac{\pi}{3}_0 {\pi (3 sec(y))^{2}} \, dy

This can be simplified to:

V=\int\limits^\frac{\pi}{3}_0 {9\pi sec^{2}(y)} \, dy

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V=9\pi\int\limits^\frac{\pi}{3}_0 {sec^{2}(y)} \, dy

which is a standard integral so we solve it to:

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V=9\pi[tan \frac{\pi}{3} - tan 0]

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V=9\pi\sqrt{3}]

6 0
4 years ago
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<u>----------------------------</u>

hope it helps....

have a great day!!

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Step-by-step explanation:

Hope this helps i learned this a while ago

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cestrela7 [59]
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