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andreev551 [17]
3 years ago
13

To show how to do this step by step

Mathematics
1 answer:
Jet001 [13]3 years ago
3 0

Answer:

to do it 5 x 10 x 4 x 5 x 6 x 7 x 3 x 2 3 x 4  x5

Step-by-step explanation:

x 3x 3x 3x3 x4 x4x4 x4x  to the power  of 5 million

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Laura rents a movie for a flat fee of $2.00 plus an additional $0.50 for each night she keeps the movie. Choose the cost functio
daser333 [38]

Answer:

The cost function that represents this scenario is c(x) = 2 + 0.50x .

Option (b) is correct .

Step-by-step explanation:

As given

Laura rents a movie for a flat fee of $2.00 plus an additional $0.50 for each night she keeps the movie.

if x equals the number of nights Laura has the movie.


Than the cost function that represents this scenario .

c(x) =  Flat fee + Cost for  x equals the number of nights Laura has the movie.


c(x) = 2 + x × 0.50

c(x) = 2 + 0.50x

Therefore the cost function that represents this scenario is c (x) = 2 + 0.50x .

Option (b) is correct .

8 0
3 years ago
Read 2 more answers
Need help with this ​
snow_tiger [21]

Answer:

x       y

15     -1

12     0

9       1

6       2

3       3

0       4

Step-by-step explanation:

This is a function table. For a linear function, find the average rate of change between the listed points called slope. Then use the slope to fill in other inputs and outputs for the function.

m = \frac{y_2-y_1}{x_2-x_1}=\frac{4-0}{0-12} =\frac{4}{-12} =- \frac{1}{3}

This means for every 3 units made in the input, the function moves down 1 output.

x       y

15     -1

12     0

9       1

6       2

3       3

0       4

6 0
3 years ago
Given an acceleration vector, initial velocity u0,v0,w0 , and initial position x0,y0,z0 , find the velocity and position vectors
dsp73

Answer:

Thus we find that velocity vector at time t is

(5t+15, 5t^2/2, 4t^2)

Step-by-step explanation:

given that acceleration vector is a funciton of time and at time t

a(t) = (5,5t, 8t)

v(t) can be obtained by integrating a(t)

v(t) = (5t, 5t^2/2, 4t^2)+(u_0,v_0,w_0)\\=(5t+15, 5t^2/2, 4t^2)

Thus we use the fact that acceleration is derivative of velocity and velocity is antiderivative of acceleration.

The arbitary constant normally used for integration C is here C vector = initial velocity (u0,v0,w0)

Position vector can be obtained by integrating v(t)

Thus we find that velocity vector at time t is

(5t+15, 5t^2/2, 4t^2)

5 0
3 years ago
What’s the slope between -14,-10 and 12,18
maria [59]

\bf (\stackrel{x_1}{-14}~,~\stackrel{y_1}{-10})\qquad (\stackrel{x_2}{12}~,~\stackrel{y_2}{18}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{18-(-10)}{12-(-14)}\implies \cfrac{18+10}{12+14}\implies \cfrac{28}{26}\implies \cfrac{14}{13}

7 0
3 years ago
Read 2 more answers
Isabel purchased a prepaid phone card for $20. Long-distance calls cost 18 cents a minute using this card. Isabel used her card
Mandarinka [93]

Answer:

20 - .07c = 17.13

20 - 17.13 = 2.87

2.87/7 = 41

Her call took 41 minutes

Step-by-step explanation:

7 0
3 years ago
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