Answer:
16 km due west
Step-by-step explanation:
The bearing of the school p from school q is 16 km due west.
To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.
Since p is directly west of q, then it implies that q must be directly east of p.
We now know the direction.
Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.
Hence, the bearing of q from p is 16 km due west.
Answer:
Density of steel = 80.73 gm/
Step-by-step explanation:
The figure is made up of cuboid and square pyramid.
Height of cuboid, h = 9 cm
Length of cuboid, l = 6 cm
Width of cuboid, w = 6 cm
Volume of cuboid is given by the formula:
Density of Wood , 
= 0.68g/
We know that formula of Density is:
Putting the values:
Total weight = 
970 = 220.32 
= 749.68 gm
Volume of pyramid is given as:
Base is a square with side 6 cm
Density of Steel/Pyramid:
Answer:
The t-critical value for 95% confidence interval is ±2.2621
Step-by-step explanation:
We are given the following information in the question:
Sample size, n = 10
Alpha, α = 0.05
We have to find the value of t-critical at 95% confidence interval.
Degree of freedom = n - 1 = 9
The t-critical value for 95% confidence interval is ±2.2621
Answer:
a = 9
Step-by-step explanation:
-6a + 2a = -36
-4a = -36
a = -36/-4
a = 9
