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3 years ago

What’s the slope between -14,-10 and 12,18

Mathematics

2 answers:

maria [59]3 years ago

7 0

$\bf (\stackrel{x_1}{-14}~,~\stackrel{y_1}{-10})\qquad (\stackrel{x_2}{12}~,~\stackrel{y_2}{18}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{18-(-10)}{12-(-14)}\implies \cfrac{18+10}{12+14}\implies \cfrac{28}{26}\implies \cfrac{14}{13}$

11111nata11111 [884]3 years ago

5 0

Answer:

28/26

Step-by-step explanation:

We can find the slope using the equation

y2-y1/x2-x1

We are give two points so lets plug them into the equation above

18-(-10)/12-(-14)

= 18+10/12+14

=28/26

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To find the product of (−2√20k)(5√8k3), first write using a single radical. Which expression is equivalent to the given product?

ad-work [718]

Answer:

Assuming the variable is included under the radical,

-40k²√(10)

Step-by-step explanation:

$(-2\sqrt{20k})(5\sqrt{8k^3})$

First we will simplify the first factor,

$-2\sqrt{20k}$

We will write 20 as a product of factors:

$-2\sqrt{4*5k}$

We know the square root of 2 is 2, so we pull a 2 out:

$-2(2)\sqrt{5k}\\\\=-4\sqrt{5k}$

Now we will simplify the second factor,

$5\sqrt{8k^3}$

We will rewrite 8 as a product of factors, as well as the variable:

$5\sqrt{2*4*k^2*k}$

The square root of 2 is 2, so we pull a 2 out. Additionally, the square root of k² is k, so we pull that out:

$5(2)(k)\sqrt{2k}\\\\=10k\sqrt{2k}$

This gives us the product

$(-4\sqrt{5k})(10k\sqrt{2k})$

Multiplying the coefficients, we have

$-4(10k)(\sqrt{5k})(\sqrt{2k})\\\\=-40k(\sqrt{5k})(\sqrt{2k})$

Multiplying the two radicals, we have

$-40k\sqrt{5k*2k}\\\\-40k\sqrt{10k^2}$

The square root of k² is k, so we pull a k out, leaving

$-40k(k)\sqrt{10}\\\\=-40k^2\sqrt{10}$

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4 years ago

Read 2 more answers

What is the average rate of change if this function interval x = -3 to x = 0

jok3333 [9.3K]

The average rate of change of the function, over the given interval is 2.

This question is incomplete, the complete question is:

What is the average rate of change of f(x) = 2x+10, if this function interval are x = -3 to x = 0.

<h3>What is the average rate of change over the interval?</h3>

The average rate of change of f(x) over the interval [a,b] is expressed as;

$\frac{f(b)-f(a)}{b-a}$

Given that;

f(x) = 2x + 10
Interval: [ -3, 0 ], a = -3 and b = 0

We substitute our values into the expression above.

$\frac{f(b)-f(a)}{b-a}\\\\\frac{f(0)-f(-3)}{0-(-3)}\\\\\frac{[2(0)+10]-[2(-3)+10]}{0-(-3)}\\\\\frac{[10]-[-6+10]}{3}\\\\\frac{[10]-[4]}{3}=\frac{6}{3}=2$

Therefore, the average rate of change of the function, over the given interval is 2.

Learn more about average rate of change: brainly.com/question/23715190

#SPJ1

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2 years ago

Of the 9-letter passwords formed by rearranging the letters AAAABBCCC (4 A's, 2 B's, and 3 C's), I select one at random. Determi

Tanya [424]

Answer:

a) 3

b) (8!/9!)-(7!/9!)

c) (1-(8!/9!))*(7!/9!)

Step-by-step explanation:

a)With 4 As ; 2Bs and 3Cs it is possible to get a palindrome if you fixed the letters C according to: (2) in the extremes of the word and the other one at the center therefore you only have palindrome in the following cases

To fill in the gaps we have 4 letters A and 2 letters B, wich we have two divide in two palindrome gaps,

AAB and BAA the palindrome is C AAB C BAA C

BAA and AAB " " is C BAA C AAB C

ABA and ABA " " is C ABA C ABA C

b) 4 A ; 2B ; 3C

We have the total number of elements 9, so the total number of possible outcomes is : 9!

Total events: 9!

if we fixed 3 C we have (the group of 3 Cs becoming one element) so the total amount of events with 3 adjacent Cs is: 7!

Therefore the probability of having 3 adjacent Cs is: 7!/9!

If we fixed only 2 Cs we have:

4 A ; 2 B ; 2C : 1C

Total number of words (events) in this case is 8! (2C becomes 1 element)

so the total numbers of events is 8! the probability in this case is 8!/9!(this value includes cases of adjacent 3 Cs previous calculated ) so this value minus the case of 3 adjacent Cs ) give us 2 adjacent C and the other no next to them

Probability (of words with 2 adjacent Cs and the other no next to them is); 8!/9! - 7!/9!

c) Probability of B apart from each other is the whole set of events minus those where 2 B are adjacent or (become 1 element)

4 A ; 2B ; 3C

Total of events 9! and events with adjacent B is 8!/9!

Therefore the probability of words with 3 adjacent Cs and 2 B separeted is

the probability of 3 adjacent Cs (7!/9!) times probability of words with no adjacent Bs wich is (1-(8!/9!))*(7!/9!)

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3 years ago

Quadratic Functions. Algebra 1

barxatty [35]

Answer:

Step-by-step explanation:

11. Write in point slope form first;

y+4 = (x+1)^2; Convert to standard form;

y=x^2+2x+1-4

y = x^2+2x-3; Final standard form

12. Convert the original point-slope form with the vertex given;

y-3 = a(x-4)^2; plug in the point (1,12) to solve for a;

12 -3 = a(1-4)^2

9 = 9a

a = 1

y-3 = (x-4)^2

y=(x-4)^2+3: Final vertex from

13. The vertex is at (-1,-4)

y +4= (x+1)^2; Factored form can mean many things;

this is the equation of the function; factor it how your teacher taught you.

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3 years ago

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a_sh-v [17]

Answer:

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Step-by-step explanation:

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3 years ago