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denis-greek [22]
3 years ago
6

the length of a boat is 10.8 m Boris buys a scale model of the boat the scale of the model is 1 to 18 work out the length of the

scale model of the boat give your answer in centimetres​
Mathematics
1 answer:
Wittaler [7]3 years ago
4 0

Answer:

The size of the scale model is 60 centimeters.

Step-by-step explanation:

Given that the length of a boat is 10.8 m, and Boris buys a scale model of the boat whose ratio is 1 to 18, to determine the length of the scale model of the boat in centimeters the following calculation must be performed:

1m = 100cm

10.8 m = (10.8 x 100) = 1080 cm

1080/18 = X

60 = X

Therefore, the size of the scale model is 60 centimeters.

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A triangle with two vertices located at (5, −8) and (5, 4) has an area of 48 square units. Determine one possible location of th
RoseWind [281]

Answer:x=1.5

Step-by-step explanation:

Given

Two points co-ordinates are given

A=(5,-8)

B=(5,4)

let other point be C =(x,y)

Area of triangle is given by

A=\begin{vmatrix}5& -8&1\\5& 4&1\\x& y&1\end{vmatrix}

A=5\left ( 4-y\right )+8\left ( 5-x\right )+1\left ( 5y-4x\right )

A=20-5y+40-8x+5y-4x

A=60-8x

and A=48 square unit

48=60-8x

x=1.5

As area is independent of y therefore at x=1.5 any value of y will give area of 48 square unit

7 0
3 years ago
Complete the table using the equation y = 3x
erica [24]

Answer:

Table is attached with values, but answers are:

(0, 0) (1, 3) (2, 6) (3, 9)

Step-by-step explanation:

y = 3x

Substitute all values.

y = 3(0)

y = 0

0, 0

y = 3(1)

y = 3

1, 3

y = 3(2)

y = 6

2, 6

y = 3(3)

y = 9

3, 9

4 0
2 years ago
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Step-by-step explanation:

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8 0
3 years ago
The cost to store is $500. The markup rate is 12% What is the marking amount? $____ What is the selling price? $ ____
wel
$500 x 0.12 = $60

$500 x 0.88 = $440

<span>What is the marking amount? $60
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8 0
3 years ago
We are standing on the top of a 1680 ft tall building and throw a small object upwards. At every second, we measure the distance
MAVERICK [17]

Answer:

a) The height of the small object 3 seconds after being launched is 2304 feet.

b) The small object ascends 128 feet between 5 seconds and 7 seconds.

c) The object will take 6 and 10 seconds after launch to reach a height of 2640 feet.

d) The object will take 21 seconds to hit the ground.

Step-by-step explanation:

The correct formula for the height of the small object is:

h(t) = -16\cdot t^{2}+256\cdot t+1680 (1)

Where:

h - Height above the ground, measured in feet.

t - Time, measured in seconds.

a) The height of the small object at given time is found by evaluating the function:

h(3\,s)= -16\cdot (3\,s)^{2}+256\cdot (3\,s)+1680

h(3\,s) = 2304\,ft

The height of the small object 3 seconds after being launched is 2304 feet.

b) First, we evaluate the function at t = 5\,s and t = 7\,s:

h(5\,s)= -16\cdot (5\,s)^{2}+256\cdot (5\,s)+1680

h(5\,s) = 2560\,s

h(7\,s)= -16\cdot (7\,s)^{2}+256\cdot (7\,s)+1680

h(7\,s) = 2688\,s

We notice that the small object ascends in the given interval.

\Delta h = h(7\,s)-h(5\,s)

\Delta h = 128\,ft

The small object ascends 128 feet between 5 seconds and 7 seconds.

c) If we know that h = 2640\,ft, then (1) is reduced into this second-order polynomial:

-16\cdot t^{2}+256\cdot t-960=0 (2)

All roots of the resulting equation come from the Quadratic Formula:

t_{1} = 10\,s and t_{2}= 6\,s

The object will take 6 and 10 seconds after launch to reach a height of 2640 feet.

d) If we know that h = 0\,ft, then (1) is reduced into this second-order polynomial:

-16\cdot t^{2}+256\cdot t +1680 = 0 (3)

All roots of the resulting equation come from the Quadratic Formula:

t_{1} = 21\,s and t_{2} = -5\,s

Just the first root offers a solution that is physically reasonable.

The object will take 21 seconds to hit the ground.

8 0
2 years ago
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