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Anvisha [2.4K]
3 years ago
14

An evolutionary biologist examined the relative fitness of Escherichia coli bacteria grown for 2000 generations, about 300 days,

at stressful acidic pH 5.5 and their parental generation, grown and preserved at pH 7.2. Both types were later grown together in an acidic medium, and their relative fitness was computed. The experiment was replicated with 6 different lines of E. coli, giving the following relative fitness values: 1.24 1.22 1.23 1.24 1.18 1.09 A relative fitness of 1 indicates that both bacteria types are equally fit. A relative fitness larger than 1 indicates that the acid-evolved line is more fit than the parental line kept at neutral pH when both are grown in acidic conditions (that is, the acid-evolved bacteria grew the most). Do the data provide evidence that bacteria evolved in acidic pH are better adapted to acidic conditions, at a significant level a = 0.05?
Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
7 0

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: fitness of a line of E. coli grown on an acidic environment.

n= 6 E. coli lines

Recorded fitness for each line: 1.24, 1.22, 1.23, 1.24, 1.18, 1.09

The relative fitness of 1 indicates that both bacteria types are equally fit.

A relative fitness larger than 1 indicates that the acid-evolved line is more fit than the parental line kept at neutral pH when both are grown in acidic conditions.

Meaning that if the average fitness of the E. coli lines grown on an acidic environment is greater than 1 then they are better adjusted to live in acidic conditions, symbolically: μ > 1

The statistic hypotheses are:

H₀: μ ≤ 1

H₁: μ > 1

α: 0.05

Assuming that the variable has a normal distribution you have to apply a one-sample t-test:

t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~~t_{n-1}

X[bar]= 1.20

S= 0.06

t_{H_0}= \frac{1.20-1}{\frac{0.06}{\sqrt{6} } } = 8.40

The p-value for this test is 0.0002

Since the p-value= 0.0002 is less than α:0.05 the decision is to reject the null hypothesis.

Then at a 5% significance level, there is significant evidence to conclude that the bacteria evolved in acidic pH are better adapted to acidic conditions.

I hope you have a SUPER day!

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Help 20 points helpppppppp math helps 20 points no linos or imma report you.
bagirrra123 [75]

Answer:

Not a right triangle

Step-by-step explanation:

We can figure out if it is a right triangle or not by using the pythagorean theorem.

a^2 + b^2 = c^2

In this case a and b are 16 and 18

In order for it to be a right triangle, c has to equal 34, in this problem.

16^2 + 18^2 = c^2

= 580^2

= \sqrt{580} = 24.0832

Since 24.0832 does not equal 34, this is not a right triangle

5 0
3 years ago
You need 660 mL of a 40% alcohol solution. On hand, you have 35% alcohol mixture. You also have a 95% alcohol mixture. How much
ozzi

Answer:

A. 605 mL of the 35% solution

B. 55 mL of the 95% solution

Step-by-step explanation:

It is given that, you need 660 mL of a 40% alcohol solution. On hand, you have 35% alcohol mixture. You also have a 95% alcohol mixture.

Let x and y be the amount of 35% alcohol solution and 95% alcohol solution (in mL) respectively.

So,

Amount equation: x+y=660        ...(1)

Alcohol equation : 0.35x+0.95y=0.40(660)\Rightarrow 0.35x+0.95y=264     ...(2)

On solving (1) and (2), we get

0.35(660-y)+0.95y=264

231-0.35y+0.95y=264

0.6y=264-231

y=\dfrac{33}{0.6}

y=55

Now, substitute y=55 in (1).

x+55=660  

x=660-55  

x=605  

Therefore, we need 605 mL of the 35% solution  and 55 mL of the 95% solution.

4 0
3 years ago
A researcher records the repair cost for 8 randomly selected washers. A sample mean of $60.46 and standard deviation of $18.36 a
Anuta_ua [19.1K]

Answer:

The critical value is T = 1.895.

The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 6

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 6 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.895, which is the critical value.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.895\frac{18.36}{\sqrt{8}} = 12.301

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 60.46 - 12.301 = $48.159

The upper end of the interval is the sample mean added to M. So it is 60.46 + 12.301 = $72.761

The 90% confidence interval for the mean repair cost for the washers is between $48.159 and $72.761

8 0
3 years ago
CAN SOMEONE PLEASE HELP
kotykmax [81]

Answer:

The first one.

Step-by-step explanation:

The symbol that you are comparing the numbers with is equal two or greater than and you have to be 48 inches or taller.

4 0
2 years ago
Solve for x.<br> A. 3<br> B. 10<br> C. 6<br> D. 1
AURORKA [14]

The values of x is 1 and 6.

According to the statement

we have two tangents which are represented by x+5 and x+1 then

we have to find the value of x to get the perfect value of tangent

so, due to interior values of tangent they are equal to each other but in opposite sign.

But here we have to find the value of x one by one.

It means

Here we take interior value of tangent and exterior value of tangent equal to each other

So, the equations become are written below

X+5= 6 then x = 1

X+1= 7 then x = 6

So, The values of x is 1 and 6.

Learn more about Tangent here brainly.com/question/4470346

#SPJ1

5 0
2 years ago
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