Question

( ；ω；)please help me​

Answer 1

Answers:

x = 7

y = 5

z = 5

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Explanation:

There are 4 distinct regions:

• The region inside circle P, but not inside circle Q. This is marked with x.
• The region in both circles P and Q. This is marked as y.
• The region inside circle Q, but not inside circle P. This is marked with z.
• The region outside both circles, but inside the rectangle. This is marked with 3

With circle P, the values of x and y must add to 12, since n(P) = 12. So x+y = 12. This solves to y = 12-x.

Similarly, y+z = 10 because n(Q) = 10, and y,z are in circle Q. This solves to y = 10-z

The values in the four regions must add to 20, as this is the total number in the universal set.

x+y+z+3 = 20

x+12-x+z = 20 ... plug in y = 12-x; solve for z

12+z+3 = 20

15+z = 20

z = 20-15

z = 5

Use this to find y

y = 10-z

y = 10-5

y = 5

Use this to find x

x+y = 12

x+5 = 12

x = 12-5

x = 7