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alexgriva [62]
3 years ago
10

Please need help on this one

Mathematics
1 answer:
tekilochka [14]3 years ago
4 0
On which one do you need help with?
You might be interested in
What is
Sergeeva-Olga [200]

Answer:

Standard form of the equation is:

∴ 3x+y=23

Step-by-step explanation:

Given equation:

y-2=-3(x-7)

To convert the given equation to standard form of equation:

A(x)+B(y)=c

Using distribution.

y-2=(-3x)+(-3\times-7)

y-2=-3x+21

Adding 2 both sides.

y-2+2=-3x+21+2

y=-3x+23

Adding 3x to both sides.

3x+y=3x-3x+23

∴ 3x+y=23

6 0
3 years ago
Simplify the Expression<br> - 1/2 (8b+3)+3b=
Anna35 [415]

Answer:

-b -3/2

Step-by-step explanation:

-1/2(8b+3) + 3B (a negative times a positive equals a negative)

1. Mutiply -1/2 by 8b and then by 3

(-1/2 x 8b -1/2 x 3) + 3b

-4b - 3/2 + 3b

2.  Add -4b + 3b = -b

-b - 3/2

5 0
2 years ago
Graph a triangle (STU) and reflect it over the y-axis to create triangle ST'U'.
lukranit [14]

The x-coordinates of \triangle S'T'U' will be the negation of the x-coordinates of \triangle STU

The line segment from S to the y-axis equals the line segment from S' to the y-axis. Similarly, the line segment from T to the y-axis equals the line segment from T' to the y-axis

See attachment for \triangle STU and \triangle S'T'U'

In order to solve this question, I will make the following assumptions.

Assume that the coordinates of \triangle STU are

S = (4,5)      

T = (5,9)

U=(3,8)

Refer to attachment for illustrations

<u>(1) Reflect </u>\triangle STU<u> over y-axis and describe the transformation</u>

To reflect \triangle STU across the y-axis, the following rule must be followed

(x,y) \to (-x,y)

This means that:

S = (4,5) \to S' = (-4,5)

T = (5,9) \to T' = (-5,9)

U=(3,8) \to U'=(-3,8)

<u>The description of the </u><u>transformation </u><u>is as follows:</u>

Notice that the signs of the x-coordinates \triangle STU and \triangle S'T'U' of both triangles are different.

In other words, if the x-coordinate of one is positive, then the other will have a negative x-coordinate; and vice versa.

<u>(2) Compare the segments and the line of reflection</u>

To reflect across the y-axis means that the reflecting line is the y-axis, itself.

The distance between a point to the y-axis is the absolute value of the x-coordinate.

So, the distance between S and the y-axis is:

S = |4| = 4

The distance between S' and the y-axis is:

S' = |-4| = 4

We can conclude that the two line segments are equal.

This is the same for other point T and T' because of the formula used above.

<u>From T and T' to the y-axis is:</u>

T =|5| =5

T' =|-5| =5

Read more at:

brainly.com/question/938117

8 0
2 years ago
How did Bill spend longer
JulsSmile [24]
How did bill spend longer .. days ... ? what
7 0
3 years ago
Owen's parents were planning a big birthday party for him.
sergiy2304 [10]

Answer:

18.75/ hour

Step-by-step explanation:

Simply divide 150 by 8.

3 0
3 years ago
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