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ollegr [7]
1 year ago
10

What is the slope of the line passing through the points (−3, −5) and (−1, −6)?

Mathematics
2 answers:
Virty [35]1 year ago
8 0

Answer:

The slope of the line passing through the points (−3, −5) and (−1, −6) is -\frac{ 1 }{ 2 } (-0.5)

Step-by-step explanation:

Equation of a straight line:

y = mx + b where m is the slope and b is the y-intercept

(x1, x2) and (y1, y2) : (−3, −5) and (−1, −6)

Calculating Slope (m).

m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}

m = \frac{ (-6) - (-5) }{ (-1) - (-3) }

m = \frac{ -6 + 5 }{ -1 + 3 }

m = -\frac{ 1 }{ 2 }

we can take this a step further by finding the equation:

Now putting value of m in equation (i)

y = -0.5x + b

Calculating Y-intercept (b).

Lets choose the first point, (-3,-5) for calculating y-intercept:

y = mx + b

-5 = -0.5(-3) + b

-5 = 1.5 + b

-6.5 = b

b = -6.5

Now putting value of b in equation

y = -0.5x + -6.5

grin007 [14]1 year ago
8 0

Answer:

-1/2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-6-(-5))/(-1-(-3))

m=(-6+5)/(-1+3)

m=-1/2

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Answer:

Step-by-step explanation:

The slope intercept form of an equation of a line is y = mx + b, where m is the slope and b is the y-intercept (the value of y when x=0).

Since the slope is (1/2), we can write:

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We want a value of b such that it forces the line to go through point (-10,9).  Enter that point in the equation and solve for b:

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9 = (1/2)*(-10) + b

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The eqyuation of a line with a slope of (1/2) and goes through point (-10,9) is:

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