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Alex777 [14]
3 years ago
5

The price of an item yesterday was $140. Today, the price fell to $63. Find the percentage decrease

Mathematics
1 answer:
DENIUS [597]3 years ago
8 0

Answer:

it is a 55% decrease

(why do i have to type at least twenty characters, just send the answer omg)

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The number 0.35 is one thousandth of what number?
Anni [7]

Answer:

0.35 is one thousandth of 350

Step-by-step explanation:

Let

x ----> the number

we know that

The number multiplied by one thousandth must be equal to 0.35

so

The linear equation that represent this situation is

(\frac{1}{1,000})x=0.35

solve for x

Multiply both sides by 1,000

1,000(\frac{1}{1,000})x=1,000(0.35)\\\\x=350

therefore

0.35 is one thousandth of 350

6 0
2 years ago
Plz help me do this
Anuta_ua [19.1K]

Answer:

Data set doesn't go to 17

Step-by-step explanation:

None of the numbers go to 17

7 0
2 years ago
Read 2 more answers
10 2/6 - 7 5/6 i know its prob easy but i need help
miv72 [106K]

Answer: 2 1/3

Explanation:

10 2/6 - 7 5/6

You can make both a fraction by multiplying the denominator by the whole number, and then adding the numerator to that number, and keeping the denominator the same. So, 10*6 = 60 and 60 + 2 = 62 and you keep the denominator as 6, which would make 62/6

7*6 = 42 and 42 + 5 = 47 so 7 5/6 becomes 47/6

10 2/6 is equivalent to 62/6

7 5/6 is equivalent to 47/6

This just makes it easier to look at.

Now you just work through the equation.

62/6 - 47/6 = 15/6

15/6 = 2 3/6 = 2 1/3

3 0
3 years ago
.....................
Allisa [31]

Answer:

30

Step-by-step explanation:

We require to calculate the volume of 1 brick

V = lbh ( l is length, b is breadth and h is height ), that is

V = 14 × 8 × 5 = 560 cm³

Now divide the volume of concrete available by the volume of 1 brick.

number of bricks made = \frac{16800}{560} = 30

5 0
3 years ago
Y=2(x+1)^2 has how many real roots
oee [108]

The equation y= 2(x+1)^2 has one real root and that is x=-1.

What is real roots of the equation?

    We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation X^2-7x+12=0 is solved, the actual roots are 3 and 4.

Here given,

=> y = 2(x+1)^2

Take y=0 then,

=> 2(x+1)^2=0

=> (x+1)^2=0

=>(x+1)=0

=> x=-1

Hence the given equation has one real root and that is x=-1.

To learn more about real roots refer the below link

brainly.com/question/24147137

#SPJ1

8 0
1 year ago
Read 2 more answers
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