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Black_prince [1.1K]
3 years ago
11

8–8 If the derivative property of phasors is multiplication of the phasor by jω, the integral property of phasors is division of

the phasor by jω. Use phasors and these properties to find the sinusoids in each of the following: υ 2 ( t ) = 1 100 d υ 1 ( t ) d t + 20 υ 1 ( t ) and υ1(t) = 10 cos(100t + 90°) V i 2 ( t ) = 10 ∫ i 1 ( t ) d t − 3 i 1 ( t ) and i1(t) = − 4 cos(5t) A

Mathematics
1 answer:
lions [1.4K]3 years ago
8 0

Answer:

solution attached below

Step-by-step explanation:

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The graph below describes the journey of a train between two cities.
Veseljchak [2.6K]

Answer:

[A] Acceleration in first 15 min = 200  km/h²

[B] Distance between two cities = 125 km

[C] Average Speed of journey =  62.5  km/hr

Step-by-step explanation:

To Solve:

Acceleration in first 15 min

Distance between two cities  

Average speed of journey

Solve:

[A] Work out the acceleration, in km/h?, in the first 15 mins.

Each horizontal block is 1/8 hr = 7.5 min

Each vertical block is 10 km/hr

Time                     Velocity  km/hr

0 Min  ( 0 hr)            0

15 Min (1/4 hr)           50

45 Min (3/4 hr)         50

60 MIn  ( 1 hr)            100

90 Min  ( 3/2 hr)        100

120 Min ( 2hr)            0

Acceleration in first 15 min  (1/4 hr)  =  (50 - 0)/(1/4 - 0)  = 50/(1/4)

= 200  km/h²

Hence, Answer for [A] = 200  km/h²

[B] Work out the distance between the two cities. $60 Velocity (in km/h)

= (1/2)(0 + 50)(1/4 - 0)  + 50 * (3/4 - 1/4)  + (1/2)(50 + 100)(1 - 3/4)  + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)

=  25/4  + 25 + 75/4   + 50 + 25

= 125

Distance between two cities = 125 km

[C] Work out the average speed of the train during 20 the journey.

Average Speed of journey = 125/2  = 62.5  km/hr

[RevyBreeze]

5 0
3 years ago
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