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Gnom [1K]
3 years ago
5

Jeb has to pay a plumber

Mathematics
1 answer:
jek_recluse [69]3 years ago
6 0
He worked 6.5 (6 and a half) hours . 40x + 65 would be the equation then you substitute 6.5 for x .
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What is the product of a number and its multiplicative inverse?<br> 2<br> 0<br> 10<br> 1
anygoal [31]

Answer:

1

Step-by-step explanation:

Example: 2×1/2=1

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2/7= 8/y <br><br> what does y equal
Scrat [10]

Step-by-step explanation:

y = 28

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3 years ago
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Find the indefinite integrals, if possible, using the formulas and techniques you have studied so far in the text.(a) 11 x4 dxTh
hoa [83]

Answer:

a) This integral can be evaluated using the basic integration rules. \int 11x^{4}dx = \frac{11}{5} x^{5}+C

b) This integral can be evaluated using the basic integration rules. \int 8x^{1}x^{4}dx=\frac{4}{3}x^{6}+C

c) This integral can be evaluated using the basic integration rules. \int 3x^{31}x^{4}dx=\frac{x^{36}}{12}+C

Step-by-step explanation:

a) \int 11x^{4}dx

In order to solve this problem, we can directly make use of the power rule of integration, which looks like this:

\int kx^{n}=k\frac{x^{n+1}}{n+1}+C

so in this case we would get:

\int 11x^{4}dx=11 \frac{x^{4+1}}{4+1}+C

\int 11x^{4}dx=11 \frac{x^{5}}{5}+C

b) \int 8x^{1}x^{4}dx

In order to solve this problem we just need to use some algebra to simplify it. By using power rules, we get that:

\int 8x^{1}x^{4}dx=\int 8x^{1+4}dx=\int 8x^{5}dx

So we can now use the power rule of integration:

\int 8x^{5}dx=\frac{8}{5+1}x^{5+1}+C

\int 8x^{5}dx=\frac{8}{6}x^{6}+C

\int 8x^{5}dx=\frac{4}{3}x^{6}+C

c) The same applies to this problem:

\int 3x^{31}x^{4}dx=\int 3x^{31+4}dx=\int 3x^{35}dx

and now we can use the power rule of integration:

\int 3x^{35}dx=\frac{3x^{35+1}}{35+1}+C

\int 3x^{35}dx=\frac{3x^{36}}{36}+C

\int 3x^{35}dx=\frac{x^{36}}{12}+C

6 0
3 years ago
Which equation represents a nonlinear function?
Hoochie [10]
I think the answer is B because that is the only answer that could make sense.
5 0
3 years ago
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