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inysia [295]
3 years ago
10

Is this correct? I need the answer quickly too lol thanks <33

Mathematics
2 answers:
777dan777 [17]3 years ago
7 0

Answer:

Step-by-step explanation:

ch4aika [34]3 years ago
6 0

Answer:

It is right

Step-by-step explanation:

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6/15=3/x solve for x
denis23 [38]

Answer:15/2


Step-by-step explanation:


3 0
4 years ago
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A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as muc
Masteriza [31]

Let x represent amount invested in the higher-yielding account.

We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be 2x.

We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.

I=Prt, where,

I = Amount of interest,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time in years.

We are told that interest rates are 6% and 10%.

6\%=\frac{6}{100}=0.06

10\%=\frac{10}{100}=0.10

Amount of interest earned from lower-yielding account: 2x(0.06)=0.12x.

Amount of interest earned from higher-yielding account: x(0.10)=0.10x.

0.12x+0.10x=6600

Let us solve for x.

0.22x=6600

\frac{0.22x}{0.22}=\frac{6600}{0.22}

x=30,000

Therefore, the man invested $30,000 at 10%.

Amount invested in the lower-yielding account would be 2x\Rightarrow 2(30,000)=60,000.

Therefore, the man invested $60,000 at 6%.

8 0
3 years ago
1. The graph shows the height of a plant after a certain amount of time measured in days.
kirza4 [7]
Wow this is a lot I am so sorry anyone smart hasn’t answered this yet cause I really do know the answer to this
4 0
3 years ago
Read 2 more answers
(x^2 - x^(1/2))/(1-x^(1/2))
Levart [38]
\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 }  } \right)  }{ \left( 1-{ x }^{ \frac { 1 }{ 2 }  } \right)  }

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot 1

\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x }  \right)  }{ \left( 1-\sqrt { x }  \right)  } \cdot \frac { \left( 1+\sqrt { x }  \right)  }{ \left( 1+\sqrt { x }  \right)  }

\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }

\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right)  }{ \left( 1-x \right)  }

\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\}  }{ \left( 1-x \right)  }

\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }\left( 1+{ x }^{ \frac { 2 }{ 2 }  } \right) -x

\\ \\ =-{ x }^{ \frac { 1 }{ 2 }  }-{ x }^{ \frac { 3 }{ 2 }  }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x
3 0
3 years ago
Read 2 more answers
What is the answer please hurry I have only 3 minutes to answer correct with a simple answer
xeze [42]
1st one I think is correct
8 0
3 years ago
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