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2 years ago

50 POINTS!!! A side of the triangle below has been extended to form an exterior angle of 148°. Find the value of x.

Mathematics

1 answer:

Bingel [31]2 years ago

5 0

Answer: x= 58°
explanation: interior angles of all triangles add up to 180.

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The owner of a snow cone stand used 1/4 gallon of syrup to make 16 cherry snow cones. She used the same amount of syrup in each.

Andreas93 [3]

Answer:

4 gallons

Step-by-step explanation: for each gallon she used one

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3 years ago

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You are considering the services of three different employment agencies, all of which can get you a job that starts at $2,000 a

Sunny_sXe [5.5K]

Answer:

Agency C offers the least expensive overall fee

Step-by-step explanation:

Alone from gross salary, you would make 24000 a year.

Agency A

24000 - ( 2000 x 0.5)

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Agency B

24000 - ( 2000 x 0.1 ) x 6

= 24000 - 200 x 6

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= 22,800

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Agency C

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2 years ago

Choose the equation below that represents the line passing through the point (1, −4) with a slope of one half

murzikaleks [220]

Can I get a like plz

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2 years ago

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A plane takes off from an airport and flies at a speed of 400km/h on a course of 120° for 2 hours. the plane then changes its co

butalik [34]

Answer:

Distance from the airport = 894.43 km

Step-by-step explanation:

Displacement and Velocity

The velocity of an object assumed as constant in time can be computed as

$\displaystyle \vec{v}=\frac{\vec{x}}{t}$

Where $\vec x$ is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

$\displaystyle \vec{x}=\vec{v}.t$

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as

$\displaystyle \vec{v_1}=$

$\displaystyle \vec{v_1}=\ km/h$

The displacement of the plane in 2 hours is

$\displaystyle \vec{x_1}=\vec{v_1}.t_1=.(2)$

$\displaystyle \vec{x_1}=km$

Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are

$\displaystyle \vec{v_2}=$

$\displaystyle \vec{v_2}=km/h$

The displacement in 1 hour is

$\displaystyle \vec{x_2}=\vec{v_2}.t_2=.(1)$

$\displaystyle \vec{x_2}=km$

The total displacement is the vector sum of both

$\displaystyle \vec{x_t}=\vec{x_1}+\vec{x_2}=+$

$\displaystyle \vec{x_t}=km$

$\displaystyle \vec{x_t}=$

The distance from the airport is the module of the displacement:

$\displaystyle |\vec{x_t}|=\sqrt{(-746.41)^2+492.82^2}$

$\displaystyle |\vec{x_t}|=894.43\ km$

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3 years ago

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Lerok [7]

Answer:

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Step-by-step explanation:

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